Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 10.5, Problem 15E

To determine

To find the surface area.

Expert Solution & Answer

Answer to Problem 15E

604 ft²

Explanation of Solution

Given Information: 2 Right angled prism and Cuboid Length(l) =10 ft., Base(b) = 82 = 4 ft., Breadth(c) = 5 ft. and Height(h) = 3 ft.

Formula Used:

Surface Area of Prism = bh+pl

where p represents the perimeter of the base, p= b+h+c

Surface Area of Cuboid = 2×(Length×Base + Base×Height + Height×Length)

Total Area = Surface Area of Prism + Surface Area of Cuboid

Calculation:

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.5, Problem 15E

Length(l) =10 ft., Base(b) = 82 = 4 ft., Breadth(c) = 5 ft. and Height(h) = 3 ft.

Perimeter p= b+h+c

Perimeter p= 4+3+5

Perimeter p= 12 ft.

Surface Area of Prism = bh+pl

Put the value of Length, Base and Height to find Surface Area of Prism

Surface Area of Prism of 1 Right angle = 4×3 + 12×10 ft²

Surface Area of Prism of 1 Right angle = 12+ 120 ft²

Surface Area of Prism of 1 Right angle = 132 ft²

Total Surface Area of Prism of 2 Right angle = 132×2=264 ft²

Given Information: Cuboid Length = 8 ft., Base = 10 ft. and Height = 5 ft.

Formula Used:

Surface Area of Cuboid = 2×(Length×Base + Base×Height + Height×Length)

Calculation:

Cuboid Length = 8 ft., Base = 10 ft. and Height = 5 ft.

Surface Area of Cuboid = 2×(Length×Base + Base×Height + Height×Length)

Put the value of Length, Base and Height to find Surface Area of Prism

Surface Area of Cuboid = 2×(8×10 + 10×5 + 5×8) ft²

Surface Area of Cuboid = 2×(80 + 50 + 40) ft²

Surface Area of Cuboid = 2×170 ft²

Surface Area of Cuboid = 340ft²

Given Information: Total Surface Area of Prism = 264 ft² and Surface Area of Cuboid = 340ft²

Formula Used:Total Surface Area = Total Surface Area of Prism + Surface Area of Cuboid

Calculation:

Total Surface Area = Total Surface Area of Prism + Surface Area of Cuboid

Now, put value of Total Surface Area of Prism and Surface Area of Cuboid to find total area.

Total Surface Area = 264 ft² + 340ft² Hence,

Total Surface Area = 604 ft²

Chapter 10.5, Problem 14E

Chapter 10.5, Problem 16E

Chapter 10 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E Ch. 10.1 - Prob. 11E Ch. 10.1 - Prob. 12E Ch. 10.1 - Prob. 13E Ch. 10.1 - Prob. 14E Ch. 10.1 - Prob. 15E Ch. 10.1 - Prob. 16E Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - Prob. 19E Ch. 10.1 - Prob. 20E Ch. 10.1 - Prob. 21E Ch. 10.1 - Prob. 22E Ch. 10.1 - Prob. 23E Ch. 10.1 - Prob. 24E Ch. 10.1 - Prob. 25E Ch. 10.1 - Prob. 26E Ch. 10.1 - Prob. 27E Ch. 10.1 - Prob. 28E Ch. 10.1 - Prob. 29E Ch. 10.1 - Prob. 30E Ch. 10.1 - Prob. 31E Ch. 10.1 - Prob. 32E Ch. 10.2 - Prob. 1C Ch. 10.2 - Prob. 2C Ch. 10.2 - Prob. 3C Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E Ch. 10.2 - Prob. 11E Ch. 10.2 - Prob. 12E Ch. 10.2 - Prob. 13E Ch. 10.2 - Prob. 14E Ch. 10.2 - Prob. 15E Ch. 10.2 - Prob. 16E Ch. 10.2 - Prob. 17E Ch. 10.2 - Prob. 18E Ch. 10.2 - Prob. 19E Ch. 10.2 - Prob. 20E Ch. 10.2 - 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