Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 10, Problem 11CP

To determine

To use the function notation to write an equation that gives the total charges for repairing a computer.

Expert Solution

Answer to Problem 11CP

The equation is, f(h)=50+35h

Explanation of Solution

Given:

The shop charges flat $50 plus $35 per hour spent on computer repair

Calculation:

Let, “h” be the number of hours spent on the computer repair.

Now forming an equation using function notation,

f(h)=50+35h

Where, f(h) is the total charges

H is the time spent on computer repair.

Graph:

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10, Problem 11CP

Conclusion:

The equation is, f(h)=50+35h

ii.

To determine

How much will the shop charge if computer repair shop spent 2.5 hours on it.

ii.

Expert Solution

Answer to Problem 11CP

The computer shop will charge $ 137.5

Explanation of Solution

Given:

The shop spends 2.5 hours on the repair, equation for the charges the computer will take f(h)=50+35h

Calculation:

Substituting the value of hours in the equation,

f(h)=50+(35×2.5)f(h)=50+87.5

Hence, the charges the computer shop will take,

$ 137.5

Conclusion:

The computer shop will charge $ 137.5

iii.

To determine

How many hours did the repair shop spent on the repairing?

iii.

Expert Solution

Answer to Problem 11CP

The repair shop spent 3.5 hours in repairing.

Explanation of Solution

Given:

The repair shop charges $172.50

Calculation:

Substituting the values of charges in the equation formed,

172.50=50+35h

Shifting left-hand side value to right hand-side,

35h=172.50−3535h=122.5

Cross-multiplying the values,

h=122.535h=3.5

Conclusion:

The repair shop spent 3.5 hours in repairing.

Chapter 10, Problem 10CP

Chapter 10, Problem 12CP

Chapter 10 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E Ch. 10.1 - Prob. 11E Ch. 10.1 - Prob. 12E Ch. 10.1 - Prob. 13E Ch. 10.1 - Prob. 14E Ch. 10.1 - Prob. 15E Ch. 10.1 - Prob. 16E Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - Prob. 19E Ch. 10.1 - Prob. 20E Ch. 10.1 - Prob. 21E Ch. 10.1 - Prob. 22E Ch. 10.1 - Prob. 23E Ch. 10.1 - Prob. 24E Ch. 10.1 - Prob. 25E Ch. 10.1 - Prob. 26E Ch. 10.1 - Prob. 27E Ch. 10.1 - Prob. 28E Ch. 10.1 - Prob. 29E Ch. 10.1 - Prob. 30E Ch. 10.1 - Prob. 31E Ch. 10.1 - Prob. 32E Ch. 10.2 - Prob. 1C Ch. 10.2 - Prob. 2C Ch. 10.2 - Prob. 3C Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E Ch. 10.2 - Prob. 11E Ch. 10.2 - Prob. 12E Ch. 10.2 - Prob. 13E Ch. 10.2 - Prob. 14E Ch. 10.2 - Prob. 15E Ch. 10.2 - Prob. 16E Ch. 10.2 - Prob. 17E Ch. 10.2 - Prob. 18E Ch. 10.2 - Prob. 19E Ch. 10.2 - Prob. 20E Ch. 10.2 - 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