Answer Explanation Given information: Side AC is 24 mm Side BC is 7 mm Formula used: Pythagorus formula, where is angle Calculation: substituting value of AC and BC to find Hypotenuse AB, square of 7 is 49 square of 24 is 576 square root of 625 is 25 For tanA , Opposite is 7 and Adjacent is 24 then, For tanB , Opposite is 24 and Adjacent is 7 then,

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 10.7, Problem 27E

To determine

To find tanA and tanB for

Expert Solution & Answer

Answer to Problem 27E

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 2

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 3

Explanation of Solution

Given information:Side AC is 24 mm

Side BC is 7 mm

Formula used:Pythagorus formula,

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 4

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 5

where Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 6 is angle

Calculation: substituting value of AC and BC to find Hypotenuse AB,

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 7

square of 7 is 49

square of 24 is 576

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 8

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 9

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 10 square root of 625 is 25

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 11

For tanA , Opposite is 7 and Adjacent is 24

then, Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 12

For tanB , Opposite is 24 and Adjacent is 7

then, Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 27E , additional homework tip 13

Chapter 10.7, Problem 26E

Chapter 10.7, Problem 28E

Chapter 10 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E Ch. 10.1 - Prob. 11E Ch. 10.1 - Prob. 12E Ch. 10.1 - Prob. 13E Ch. 10.1 - Prob. 14E Ch. 10.1 - Prob. 15E Ch. 10.1 - Prob. 16E Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - Prob. 19E Ch. 10.1 - Prob. 20E Ch. 10.1 - Prob. 21E Ch. 10.1 - Prob. 22E Ch. 10.1 - Prob. 23E Ch. 10.1 - Prob. 24E Ch. 10.1 - Prob. 25E Ch. 10.1 - Prob. 26E Ch. 10.1 - Prob. 27E Ch. 10.1 - Prob. 28E Ch. 10.1 - Prob. 29E Ch. 10.1 - Prob. 30E Ch. 10.1 - Prob. 31E Ch. 10.1 - Prob. 32E Ch. 10.2 - Prob. 1C Ch. 10.2 - Prob. 2C Ch. 10.2 - Prob. 3C Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E Ch. 10.2 - Prob. 11E Ch. 10.2 - Prob. 12E Ch. 10.2 - Prob. 13E Ch. 10.2 - Prob. 14E Ch. 10.2 - Prob. 15E Ch. 10.2 - Prob. 16E Ch. 10.2 - Prob. 17E Ch. 10.2 - Prob. 18E Ch. 10.2 - Prob. 19E Ch. 10.2 - Prob. 20E Ch. 10.2 - 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