Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 10.5, Problem 17E

(a)

To determine

To compare area of base of new cylinder compare to original cylinder.

(a)

Expert Solution
Check Mark

Answer to Problem 17E

4 : 1

Explanation of Solution

Given Information: For original cylinder = Radius = r in and Height = h in.

For new cylinder = Radius = 2r in and Height = 2h in

Formula Used:

Area of Base= π×(radius)2

Calculation:

Area of Base of new cylinder = π×(radius)2

For new cylinder = Radius = 2r in and Height = 2h in

Area of Base of new cylinder = π×(2r)2

Hence,

Area of Base of new cylinder = 4πr2

Area of Base of original cylinder = π×(radius)2

For original cylinder = Radius = r in and Height = h in

Area of Base of original cylinder = π×(r)2

Hence,

Area of Base of original cylinder = πr2

Hence, Ratio

Area of Base of new cylinder : Area of Base of original cylinder

  4πr2 : πr2

4 : 1

(b)

To determine

To compare circumference of base of new cylinder compare to original cylinder.

(b)

Expert Solution
Check Mark

Answer to Problem 17E

2 : 1

Explanation of Solution

Given Information: For original cylinder = Radius = r in and Height = h in.

For new cylinder = Radius = 2r in and Height = 2h in

Formula Used:

Circumference of Base = 2π×radius+2×height

Calculation:

Circumference of Base of new cylinder = 2π×radius+2×height

For new cylinder = Radius = 2r in and Height = 2h in

Circumference of Base of new cylinder = 2π×(2r)+2×(2h)

Hence,

Circumference of Base of new cylinder = 4πr+4h=4(πr+h)

Circumference of Base of original cylinder = 2π×radius+2×height

For original cylinder = Radius = r in and Height = h in

Circumference of Base of original cylinder = 2πr+2h

Hence,

Circumference of Base of original cylinder = 2(πr+h)

Hence, Ratio

Circumference of Base of new cylinder : Circumference of Base of original cylinder

  4(πr+h):2(πr+h)

2 : 1

(c)

To determine

To compare surface area of base of new cylinder compare to original cylinder.

(c)

Expert Solution
Check Mark

Answer to Problem 17E

4 : 1

Explanation of Solution

Given Information: For original cylinder = Radius = r in and Height = h in.

For new cylinder = Radius = 2r in and Height = 2h in

Formula Used:

Surface area of Base = 2π×radius(height+radius)

Calculation:

Surface area of Base of new cylinder = 2π×radius(height+radius)

For new cylinder = Radius = 2r in and Height = 2h in

Surface area of Base of new cylinder = 2π×(2r){(2h)+(2r)}

Hence,

Surface area of Base of new cylinder = 4πr×2(h+r)

Surface area of Base of new cylinder = 8πr(h+r)

Surface area of Base of original cylinder = 2π×radius(height+radius)

For original cylinder = Radius = r in and Height = h in

Surface area of Base of original cylinder = 2πr(h+r)

Hence, Ratio

Surface area of Base of new cylinder : Surface area of Base of original cylinder

  8πr(h+r):2πr(h+r)

4 : 1

Chapter 10 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10ECh. 10.1 - Prob. 11ECh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.1 - Prob. 29ECh. 10.1 - Prob. 30ECh. 10.1 - Prob. 31ECh. 10.1 - Prob. 32ECh. 10.2 - Prob. 1CCh. 10.2 - Prob. 2CCh. 10.2 - Prob. 3CCh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.3 - Prob. 1CCh. 10.3 - Prob. 2CCh. 10.3 - Prob. 3CCh. 10.3 - Prob. 4CCh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Prob. 24ECh. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - Prob. 28ECh. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - Prob. 31ECh. 10.3 - Prob. 32ECh. 10.3 - Prob. 33ECh. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 41ECh. 10.3 - Prob. 42ECh. 10.3 - Prob. 43ECh. 10.4 - Prob. 1CCh. 10.4 - Prob. 2CCh. 10.4 - Prob. 3CCh. 10.4 - Prob. 4CCh. 10.4 - Prob. 5CCh. 10.4 - Prob. 6CCh. 10.4 - Prob. 7CCh. 10.4 - Prob. 8CCh. 10.4 - Prob. 1ECh. 10.4 - Prob. 2ECh. 10.4 - Prob. 3ECh. 10.4 - Prob. 4ECh. 10.4 - Prob. 5ECh. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Prob. 10ECh. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - Prob. 16ECh. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.4 - Prob. 29ECh. 10.4 - Prob. 30ECh. 10.4 - Prob. 31ECh. 10.4 - Prob. 32ECh. 10.4 - Prob. 33ECh. 10.4 - Prob. 34ECh. 10.4 - Prob. 35ECh. 10.4 - Prob. 36ECh. 10.4 - Prob. 37ECh. 10.4 - Prob. 38ECh. 10.4 - Prob. 39ECh. 10.4 - Prob. 40ECh. 10.4 - Prob. 41ECh. 10.4 - Prob. 42ECh. 10.4 - Prob. 43ECh. 10.4 - Prob. 44ECh. 10.4 - Prob. 45ECh. 10.5 - Prob. 1CCh. 10.5 - Prob. 2CCh. 10.5 - Prob. 1ECh. 10.5 - Prob. 2ECh. 10.5 - Prob. 3ECh. 10.5 - Prob. 4ECh. 10.5 - Prob. 5ECh. 10.5 - Prob. 6ECh. 10.5 - Prob. 7ECh. 10.5 - Prob. 8ECh. 10.5 - Prob. 9ECh. 10.5 - Prob. 10ECh. 10.5 - Prob. 11ECh. 10.5 - Prob. 12ECh. 10.5 - Prob. 13ECh. 10.5 - Prob. 14ECh. 10.5 - Prob. 15ECh. 10.5 - Prob. 16ECh. 10.5 - Prob. 17ECh. 10.5 - Prob. 19ECh. 10.5 - Prob. 20ECh. 10.5 - Prob. 21ECh. 10.5 - Prob. 22ECh. 10.5 - Prob. 23ECh. 10.5 - Prob. 24ECh. 10.5 - Prob. 25ECh. 10.5 - Prob. 26ECh. 10.5 - Prob. 27ECh. 10.5 - Prob. 28ECh. 10.5 - Prob. 29ECh. 10.5 - Prob. 30ECh. 10.5 - Prob. 31ECh. 10.6 - Prob. 1CCh. 10.6 - Prob. 2CCh. 10.6 - Prob. 1ECh. 10.6 - Prob. 2ECh. 10.6 - Prob. 3ECh. 10.6 - Prob. 4ECh. 10.6 - Prob. 5ECh. 10.6 - Prob. 6ECh. 10.6 - Prob. 7ECh. 10.6 - Prob. 8ECh. 10.6 - Prob. 9ECh. 10.6 - Prob. 10ECh. 10.6 - Prob. 11ECh. 10.6 - Prob. 12ECh. 10.6 - Prob. 13ECh. 10.6 - Prob. 14ECh. 10.6 - Prob. 15ECh. 10.6 - Prob. 16ECh. 10.6 - Prob. 17ECh. 10.6 - Prob. 18ECh. 10.6 - Prob. 19ECh. 10.6 - Prob. 20ECh. 10.6 - Prob. 21ECh. 10.6 - Prob. 22ECh. 10.6 - Prob. 23ECh. 10.6 - Prob. 24ECh. 10.6 - Prob. 25ECh. 10.6 - Prob. 26ECh. 10.6 - Prob. 27ECh. 10.6 - Prob. 28ECh. 10.6 - Prob. 29ECh. 10.6 - Prob. 31ECh. 10.6 - Prob. 32ECh. 10.6 - Prob. 33ECh. 10.6 - Prob. 34ECh. 10.6 - Prob. 35ECh. 10.6 - Prob. 36ECh. 10.6 - Prob. 37ECh. 10.6 - Prob. 38ECh. 10.6 - Prob. 39ECh. 10.6 - Prob. 40ECh. 10.6 - Prob. 41ECh. 10.7 - Prob. 1CCh. 10.7 - Prob. 2CCh. 10.7 - Prob. 3CCh. 10.7 - Prob. 4CCh. 10.7 - Prob. 1ECh. 10.7 - Prob. 2ECh. 10.7 - Prob. 3ECh. 10.7 - Prob. 4ECh. 10.7 - Prob. 5ECh. 10.7 - Prob. 6ECh. 10.7 - Prob. 7ECh. 10.7 - Prob. 8ECh. 10.7 - Prob. 9ECh. 10.7 - Prob. 10ECh. 10.7 - Prob. 11ECh. 10.7 - Prob. 12ECh. 10.7 - Prob. 13ECh. 10.7 - Prob. 14ECh. 10.7 - Prob. 15ECh. 10.7 - Prob. 16ECh. 10.7 - Prob. 17ECh. 10.7 - Prob. 18ECh. 10.7 - Prob. 19ECh. 10.7 - Prob. 20ECh. 10.7 - Prob. 21ECh. 10.7 - Prob. 22ECh. 10.7 - Prob. 23ECh. 10.7 - Prob. 24ECh. 10.7 - Prob. 25ECh. 10.7 - Prob. 26ECh. 10.7 - Prob. 27ECh. 10.7 - Prob. 28ECh. 10.7 - Prob. 29ECh. 10.7 - Prob. 30ECh. 10.7 - Prob. 31ECh. 10.7 - Prob. 32ECh. 10.8 - Prob. 1CCh. 10.8 - Prob. 2CCh. 10.8 - Prob. 3CCh. 10.8 - Prob. 1ECh. 10.8 - Prob. 2ECh. 10.8 - Prob. 3ECh. 10.8 - Prob. 4ECh. 10.8 - Prob. 5ECh. 10.8 - Prob. 6ECh. 10.8 - Prob. 7ECh. 10.8 - Prob. 8ECh. 10.8 - Prob. 9ECh. 10.8 - Prob. 10ECh. 10.8 - Prob. 11ECh. 10.8 - Prob. 12ECh. 10.8 - Prob. 13ECh. 10.8 - Prob. 14ECh. 10.8 - Prob. 15ECh. 10.8 - Prob. 16ECh. 10.8 - Prob. 17ECh. 10.8 - Prob. 18ECh. 10.8 - Prob. 19ECh. 10.8 - Prob. 20ECh. 10.8 - Prob. 21ECh. 10.8 - Prob. 22ECh. 10.8 - Prob. 23ECh. 10.8 - Prob. 24ECh. 10.8 - Prob. 25ECh. 10.8 - Prob. 26ECh. 10.8 - Prob. 27ECh. 10.8 - Prob. 28ECh. 10.8 - Prob. 29ECh. 10.8 - Prob. 30ECh. 10.8 - Prob. 31ECh. 10.8 - Prob. 32ECh. 10.8 - Prob. 33ECh. 10.8 - Prob. 34ECh. 10 - Prob. 1PSQCh. 10 - Prob. 2PSQCh. 10 - Prob. 3PSQCh. 10 - Prob. 4PSQCh. 10 - Prob. 5PSQCh. 10 - Prob. 6PSQCh. 10 - Prob. 7PSQCh. 10 - Prob. 8PSQCh. 10 - Prob. 9PSQCh. 10 - Prob. 10PSQCh. 10 - Prob. 11PSQCh. 10 - Prob. 1MCQCh. 10 - Prob. 2MCQCh. 10 - Prob. 3MCQCh. 10 - Prob. 4MCQCh. 10 - Prob. 5MCQCh. 10 - Prob. 6MCQCh. 10 - Prob. 7MCQCh. 10 - Prob. 8MCQCh. 10 - Prob. 9MCQCh. 10 - Prob. 10MCQCh. 10 - Prob. 11MCQCh. 10 - Prob. 1CRCh. 10 - Prob. 2CRCh. 10 - Prob. 3CRCh. 10 - Prob. 4CRCh. 10 - Prob. 5CRCh. 10 - Prob. 6CRCh. 10 - Prob. 7CRCh. 10 - Prob. 8CRCh. 10 - Prob. 9CRCh. 10 - Prob. 10CRCh. 10 - Prob. 11CRCh. 10 - Prob. 12CRCh. 10 - Prob. 13CRCh. 10 - Prob. 14CRCh. 10 - Prob. 15CRCh. 10 - Prob. 16CRCh. 10 - Prob. 17CRCh. 10 - Prob. 18CRCh. 10 - Prob. 19CRCh. 10 - Prob. 20CRCh. 10 - Prob. 21CRCh. 10 - Prob. 22CRCh. 10 - Prob. 23CRCh. 10 - Prob. 24CRCh. 10 - Prob. 25CRCh. 10 - Prob. 26CRCh. 10 - Prob. 1CTCh. 10 - Prob. 2CTCh. 10 - Prob. 3CTCh. 10 - Prob. 4CTCh. 10 - Prob. 5CTCh. 10 - Prob. 6CTCh. 10 - Prob. 7CTCh. 10 - Prob. 8CTCh. 10 - Prob. 9CTCh. 10 - Prob. 10CTCh. 10 - Prob. 11CTCh. 10 - Prob. 12CTCh. 10 - Prob. 13CTCh. 10 - Prob. 14CTCh. 10 - Prob. 15CTCh. 10 - Prob. 1CSTCh. 10 - Prob. 2CSTCh. 10 - Prob. 3CSTCh. 10 - Prob. 4CSTCh. 10 - Prob. 5CSTCh. 10 - Prob. 6CSTCh. 10 - Prob. 7CSTCh. 10 - Prob. 8CSTCh. 10 - Prob. 9CSTCh. 10 - Prob. 10CSTCh. 10 - Prob. 11CSTCh. 10 - Prob. 12CSTCh. 10 - Prob. 2PTTSCh. 10 - Prob. 3PTTSCh. 10 - Prob. 4PTTSCh. 10 - Prob. 5PTTSCh. 10 - Prob. 6PTTSCh. 10 - Prob. 7PTTSCh. 10 - Prob. 8PTTSCh. 10 - Prob. 9PTTSCh. 10 - Prob. 10PTTSCh. 10 - Prob. 11PTTSCh. 10 - Prob. 12PTTSCh. 10 - Prob. 13PTTSCh. 10 - Prob. 14PTTSCh. 10 - Prob. 15PTTSCh. 10 - Prob. 16PTTSCh. 10 - Prob. 1CPCh. 10 - Prob. 2CPCh. 10 - Prob. 3CPCh. 10 - Prob. 4CPCh. 10 - Prob. 5CPCh. 10 - Prob. 6CPCh. 10 - Prob. 7CPCh. 10 - Prob. 8CPCh. 10 - Prob. 9CPCh. 10 - Prob. 10CPCh. 10 - Prob. 11CPCh. 10 - Prob. 12CPCh. 10 - Prob. 13CPCh. 10 - Prob. 14CPCh. 10 - Prob. 16CPCh. 10 - Prob. 17CPCh. 10 - Prob. 18CPCh. 10 - Prob. 19CPCh. 10 - Prob. 20CPCh. 10 - Prob. 21CPCh. 10 - Prob. 22CPCh. 10 - Prob. 23CPCh. 10 - Prob. 25CPCh. 10 - Prob. 26CPCh. 10 - Prob. 27CPCh. 10 - Prob. 28CPCh. 10 - Prob. 29CPCh. 10 - Prob. 30CPCh. 10 - Prob. 31CPCh. 10 - Prob. 32CPCh. 10 - Prob. 33CPCh. 10 - Prob. 34CP

Additional Math Textbook Solutions

Find more solutions based on key concepts
Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Text book image
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Text book image
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Text book image
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
Text book image
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
The surface area and volume of cone, cylinder, prism and pyramid; Author: AtHome Tuition;https://www.youtube.com/watch?v=SlaQmaJCOt8;License: Standard YouTube License, CC-BY