Chapter 10, Problem 21CP

To determine

To calculate the length of the third leg of the triangle

Answer to Problem 21CP

  $30$ $centimeters$

Explanation of Solution

Given information:

  $hypotenuse$$=$ $32.5$ $centimeters$

One leg $=$ $12.5$ $centimeters$

Formula used:

Pythagoras Theoram

  $hypotenus{e}^2$$=$ $onele{g}^2$ $+$ $\sec ondle{g}^2$

Calculation:

Substituting the value of one leg and hypotenuse

  ${(32.5)}^2$$=$ ${(12.5)}^2$ $+$ $\sec ondle{g}^2$

Calculate the value of second leg

  $\sec ondle{g}^2$$=$ $1056.25$ $-$ $156.25$$=$ $900$ $centimeters$

solving the square on the left hand side

  $\sec ondleg$$=$ $30$ $centimeters$ .