a.
To calculate the surface area of pyramid.
a.
Answer to Problem 29E
Explanation of Solution
Given Information: Pyramid Base b = 8 ft., Radius
Formula Used:
Surface area of square pyramid =
Calculation:
Surface area of square pyramid =
Now, find Slant Height s.
Slant Height of Pyramid
Radius r = 4 ft., Height h = 3 ft.
Now put the value of r and h to find Slant Height of Pyramid
Slant Height of Pyramid
So,
Slant Height of Pyramid
So,
Slant Height of Pyramid
Hence,
Slant Height of Pyramid
Surface area of square pyramid =
Base b = 8 ft. and Slant Height s = 5 ft.
Now put the value of b and s to find Surface area of square pyramid
Surface area of square pyramid =
So,
Surface area of square pyramid =
So,
Surface area of square pyramid =
Hence,
Surface area of square pyramid =
b.
To calculate the surface area of cone.
b.
Answer to Problem 29E
Explanation of Solution
Given Information: Cone Diameter d = 8 ft., Height h = 3 ft. and
Formula Used:
Surface area of Cone =
Calculation:
Surface area of Cone =
Diameter d = 8 ft., Height h = 3 ft. and
First find Radius r.
Hence,
Radius =
Put the value of diameter to find radius of Cone
Radius =
So,
Radius r = 4 ft.
Now, find Slant Height s.
Slant Height of Cone
Radius r = 4 ft., Height h = 3 ft.
Now put the value of r and h to find Slant Height of Cone
Slant Height of Cone
So,
Slant Height of Cone
So,
Slant Height of Cone
Hence,
Slant Height of Cone
Surface area of Cone =
Radius r = 4 ft., Slant Height s = 5 ft.
Now put the value of r, s and
Surface area of Cone =
So,
Surface area of Cone =
So,
Surface area of Cone =
So,
Surface area of Cone =
Hence,
Surface area of Cone =
c.
To compare pyramid or cone have the greater area .
c.
Answer to Problem 29E
Surface area of square pyramid is greater than Surface area of Cone.
Explanation of Solution
Given Information:
Surface area of square pyramid =
Surface area of Cone =
Formula Used:Comparison
Calculation:
As Checked,
Surface area of square pyramid =
Surface area of Cone =
Surface area of square pyramid is greater than Surface area of Cone.
Chapter 10 Solutions
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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