Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 10.8, Problem 20E

To determine

To find the volume of large and small cone.

Expert Solution

Answer to Problem 20E

The volume of larger cone is 20.93 inch³and volume of smaller cone is 0.17 inch³

Explanation of Solution

Given Information:

The diameter of larger cone is 4 inch and height is 5 inch. The diameter of smaller cone is 0.8 inch and height is 1 inch.

Formula Used: v=(πr2h)3

Calculation:

For larger cone,

Diameter (d) of the cone is 0.8 inch,

Hence, radius (r) of cone is 0.4 inch

Substituting values of radius and height

v=3.14×22×53v=62.83

Hence, volume of larger cone is,

20.93 inch³ ----------------(1)

For smaller cone,

Diameter (d) of the cone is 0.8 inch,

Hence, radius (r) of cone is 0.4 inch

Substituting values of radius and height

v=3.14×0.42×13v=0.503

Hence, volume of larger cone is,

0.17 inch³. __________(2)

ii.

To determine

To find the difference between the volumes of the larger and smaller cone

ii.

Expert Solution

Answer to Problem 20E

The difference between the cones is 20.86 inch³

Explanation of Solution

Given Information:

The volume of larger cone is 20.93 inch³ and the volume of smaller cone is 0.17 inch³.

Calculation:

The difference between volumes of cone the cones is= volume of larger cone (1) - volume of smaller cone(2)

Substituting the values of larger cone and smaller cone,

= 20.93-0.17

= 20.86 inch³----------------------(3)

Conclusion:

The difference in volume of cones is 20.86 inch³

iii.

To determine

The volume of the cylinder

iii.

Expert Solution

Answer to Problem 20E

The volume of the cylinder is 0.75 inch³

Explanation of Solution

Given Information:

The height of cylinder is 1.5 inch and diameter is 0.8 inch

Formula Used:Volume of cylinder is,

v=πr2h

Calculation:

Diameter (d) of the cone is 0.8 inch,

Hence, radius (r) of cone is 0.4 inch

Substituting values of radius and height:

v=3.14×0.82×1.5

Hence, the volume of cylinder is:

0.75 inch³ --------------(4)

Conclusion:

The volume of cylinder is 0.75 inch³

iv.

To determine

TO-DETERMINE the volume of the funnel

iv.

Expert Solution

Answer to Problem 20E

The volume of funnel is 21.61 inch³

Explanation of Solution

Given Information: The volume of the cylinder of the cone is 0.75 inch³and the volume difference between the cones is 20.86 inch³

Calculation:

The volume of funnel is = volume of cylinder (4) + volume difference between the cones (3)

v = 20.86 + 0.75

Hence, volume of funnel is,

v = 21.61 inch³

Conclusion:

Volume of the funnel is 21.61 inch³

Chapter 10.8, Problem 19E

Chapter 10.8, Problem 21E

Chapter 10 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E Ch. 10.1 - Prob. 11E Ch. 10.1 - Prob. 12E Ch. 10.1 - Prob. 13E Ch. 10.1 - Prob. 14E Ch. 10.1 - Prob. 15E Ch. 10.1 - Prob. 16E Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - Prob. 19E Ch. 10.1 - Prob. 20E Ch. 10.1 - Prob. 21E Ch. 10.1 - Prob. 22E Ch. 10.1 - Prob. 23E Ch. 10.1 - Prob. 24E Ch. 10.1 - Prob. 25E Ch. 10.1 - Prob. 26E Ch. 10.1 - Prob. 27E Ch. 10.1 - Prob. 28E Ch. 10.1 - Prob. 29E Ch. 10.1 - Prob. 30E Ch. 10.1 - Prob. 31E Ch. 10.1 - Prob. 32E Ch. 10.2 - Prob. 1C Ch. 10.2 - Prob. 2C Ch. 10.2 - Prob. 3C Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E Ch. 10.2 - Prob. 11E Ch. 10.2 - Prob. 12E Ch. 10.2 - Prob. 13E Ch. 10.2 - Prob. 14E Ch. 10.2 - Prob. 15E Ch. 10.2 - Prob. 16E Ch. 10.2 - Prob. 17E Ch. 10.2 - Prob. 18E Ch. 10.2 - Prob. 19E Ch. 10.2 - Prob. 20E Ch. 10.2 - 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