Mechanics of Materials (MindTap Course List)
9th Edition
ISBN: 9781337093347
Author: Barry J. Goodno, James M. Gere
Publisher: Cengage Learning
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Textbook Question
Chapter 1, Problem 1.10.6P
Cable DB supports canopy beam OABC as shown in the figure. Find the required cross-sectional area of cable BD if the allowable normal stress is 125 MPa. Determine the required diameter of the pins at 0, B, and D if the allowable stress in shear is 80 MPa. Assume that canopy beam weight is w = 8 kN. note The pins at 0, A, D and D are in double shear. Consider only the weight of the canopy; disregard the weight of cable DB.
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A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35)
200 = 139.3 + 35c₂
200 - 139.3 = 35c₂
60.7 = 35c₂
c₂ = 60.7/35
Short spring (c₂) = 1.73 N/mm
According to my study book, the correct answer is 4.82N/mm
What is wrong with the calculating?
What is the reason for this composition?
Homework: ANOVA Table for followed design
B
AB
Dr
-1
-1
1
(15.18,12)
1
-1
-1
(45.48.51)
-1
1
-1
(25,28,19)
1
1
(75.75,81)
Chapter 1 Solutions
Mechanics of Materials (MindTap Course List)
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