Two steel tubes are joined at B by four pins ( d p = 11 mm), as shown in the cross section a—a in the fiaure. The outer diameters of the tubes are d A B = 41 mm and d B C = 28 mm. The wall thickness are t A B = 6.5 mm and t B C = 7.5 mm. The yield stress in tension for the steel is sy = 200 MPa and the ultimate stress in tension is ?? U : = 340 MPa. The corresponding yield and ultimate values in shear for the pm are 80 MPa and 140 MPa, respectively. Finally, the yield and ultimate values in bearing R between the pins and the tubes are 260 MPa, and 450 MPa, respectively. Assume that the factors safety with respect to yield stress and ultimate stress are 3.5 and 4.5. respectively. (a) Calculate the allowable tensile force P a l l o w considering tension in the tube (b) Recompute P a l l o w for shear in the pins. (c)Finaly, recomputed P a l l o w for bearing between the pm and the tubes. Which is the tubes. Which is the controlling value value of P?
Two steel tubes are joined at B by four pins ( d p = 11 mm), as shown in the cross section a—a in the fiaure. The outer diameters of the tubes are d A B = 41 mm and d B C = 28 mm. The wall thickness are t A B = 6.5 mm and t B C = 7.5 mm. The yield stress in tension for the steel is sy = 200 MPa and the ultimate stress in tension is ?? U : = 340 MPa. The corresponding yield and ultimate values in shear for the pm are 80 MPa and 140 MPa, respectively. Finally, the yield and ultimate values in bearing R between the pins and the tubes are 260 MPa, and 450 MPa, respectively. Assume that the factors safety with respect to yield stress and ultimate stress are 3.5 and 4.5. respectively. (a) Calculate the allowable tensile force P a l l o w considering tension in the tube (b) Recompute P a l l o w for shear in the pins. (c)Finaly, recomputed P a l l o w for bearing between the pm and the tubes. Which is the tubes. Which is the controlling value value of P?
Solution Summary: The author explains the maximum tensile force considering tension in the tube.
Two steel tubes are joined at B by four pins (dp= 11 mm), as shown in the cross section a—a in the fiaure. The outer diameters of the tubes are dAB= 41 mm and dBC= 28 mm. The wall thickness are tAB= 6.5 mm and tBC= 7.5 mm. The yield stress in tension for the steel is sy = 200 MPa and the ultimate stress in tension is ??U:= 340 MPa. The corresponding yield and ultimate values in shear for the pm are 80 MPa and 140 MPa, respectively. Finally, the yield and ultimate values in bearing R between the pins and the tubes are 260 MPa, and 450 MPa, respectively. Assume that the factors safety with respect to yield stress and ultimate stress are 3.5 and 4.5. respectively. (a) Calculate the allowable tensile force P allowconsidering tension in the tube (b) Recompute P allowfor shear in the pins.(c)Finaly, recomputed Pallowfor bearing between the pm and the tubes. Which is the tubes. Which is the controlling value value of P?
A virtual experiment is designed to determine the effect of friction on the timing and speed
of packages being delivered to a conveyor belt and the normal force applied to the tube.
A package is held and then let go at the edge of a circular shaped tube of radius R = 5m.
The particle at the bottom will transfer to the conveyor belt, as shown below.
Run the simulations for μ = 0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6 and determine the time and speed at
which the package is delivered to the conveyor belt. In addition, determine the maximum
normal force and its location along the path as measured by angle 0.
Submit in hardcopy form:
(0) Free Body Diagram, equations underneath, derivations
(a) Your MATLAB mfile
(b) A table listing the values in 5 columns:
μ, T (time of transfer), V (speed of transfer), 0 (angle of max N), Nmax (max N)
(c) Based on your results, explain in one sentence what you think will happen to the
package if the friction is increased even further, e.g. μ = 0.8.
NOTE: The ODE is…
Patm = 1 bar
Piston
m = 50 kg
5 g of Air
T₁ = 600 K
P₁ = 3 bar
Stops
A 9.75 x 10-3 m²
FIGURE P3.88
Assume a Space Launch System (Figure 1(a)) that is approximated as a cantilever undamped single degree of freedom (SDOF) system with a mass at its free end (Figure 1(b)). The cantilever is assumed to be massless. Assume a wind load that is approximated with a concentrated harmonic forcing function p(t) = posin(ωt) acting on the mass. The known properties of the SDOF and the applied forcing function are given below. • Mass of SDOF: m =120 kip/g • Acceleration of gravity: g = 386 in/sec2 • Bending sectional stiffness of SDOF: EI = 1015 lbf×in2 • Height of SDOF: h = 2000 inches • Amplitude of forcing function: po = 6 kip • Forcing frequency: f = 8 H
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