Concept explainers
(a)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(a)
Explanation of Solution
The given organic compound is as follows:
The name of the compound is 2-butanol.
Here, hydroxyl group is attached to the secondary carbon thus, it is a secondary alcohol.
(b)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(b)
Explanation of Solution
The given organic compound is as follows:
The name of the above compound is 5-bromo-3-hexanol.
Here, the hydroxyl group is at secondary carbon thus, it is a secondary alcohol.
(c)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(c)
Explanation of Solution
The given organic compound is as follows:
The name of the compound is 2-propyl-1-pentanol.
Now, there is hydroxyl group at primary position thus, it is a primary alcohol.
(d)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(d)
Explanation of Solution
The given organic compound is as follows:
The name of the compound is (S)-1-chloro-2-propanol. There is a hydroxyl group at secondary carbon thus, it is a secondary alcohol.
(e)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(e)
Explanation of Solution
The given organic compound is as follows:
The name of the above compound is 1-ethylcyclobutanol. The hydroxyl group is at tertiary carbon thus, it is a tertiary alcohol.
(f)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(f)
Explanation of Solution
The given organic compound is as follows:
The name of the compound is (1R,2R)-2bromocyclodecanol.
In the above compound, the hydroxyl group is at secondary position thus, this is a secondary alcohol.
(g)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(g)
Explanation of Solution
The given organic compound is as follows:
The name of the compound is 2, 2-bis(hydroxylmethyl)propane-1,3-
(h)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(h)
Explanation of Solution
The given organic compound is as follows:
The name of the molecule is (2S,3R)-2,3-dihydroxybutane-1,2-diol. The hydroxyl group at first and fourth carbon atoms is primary and the other two hydroxyl groups are at second and third carbon atoms which are secondary.
(i)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(i)
Explanation of Solution
The given organic compound is as follows:
The name of the compound is cis-2-(2-hydroxylethyl)cyclopentanol. Here, the hydroxyl group is at secondary carbon atom of the cyclopentyl ring and the other hydroxyl group is attached to the primary carbon atom.
(j)
Interpretation: The name of the given alcohol needs to be determined, the stereochemistry (if present) needs to be indicated and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(j)
Explanation of Solution
The given compound is as follows:
The name of the compound is (2R)-2-chloro-2-methyl-1-butanol. The hydroxyl group is at primary carbon atom thus, it is primary alcohol.
(k)
Interpretation: The name of the given alcohol and its all possible stereoisomers needs to be determined and it needs to be labeled as primary, secondary and tertiary alcohol.
Concept Introduction: An alcohol can be classified as primary, secondary and tertiary deepening on the number of hydrogen atoms attached to the C atom to which the hydroxyl group is attached. If the number of H atoms are two, the alcohol is primary in nature, if there is only 1 H atom attached, then the alcohol is secondary and if there is no H atom attached to the C atom then the alcohol is tertiary.
(k)
Explanation of Solution
The given structure is as follows:
Since, there is no chiral center thus, there will be no possible stereoisomers.
The name of the given alcohol is 2, 2, 4, 4-tetramethylcyclobutane-1, 3-diol. Both the −OH groups are on the C atom with 1 H atom each thus, both are secondary alcohols.
Want to see more full solutions like this?
Chapter 8 Solutions
ORGANIC CHEMISTRY (LL)-PACKAGE
- When anisole is treated with excess bromine, the reaction gives a product which shows two singlets in 1H NMR. Draw the product.arrow_forward(ii) Draw a reasonable mechanism for the following reaction: CI NaOH heat OH (hint: SNAr Reaction) :arrow_forwardDraw the major product in each of the following reaction:arrow_forward
- Draw the mechanism for the following Friedel-Craft reaction. AlBr3 Brarrow_forward(a) Draw the structures of A and B in the following reaction. (i) NaNH2, NH3(1) A + B (ii) H3O+arrow_forwardFor the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 →> NO₂+ NO3_(K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → → NO2 + O2 + NO (K2) NO + N2O5- NO2 + NO2 + NO2 (K3) d[N₂O5] __2k‚k₂[N2O5] Indicate whether the following rate expression is acceptable: dt k₁₁+ k₂arrow_forward
- Consider the following decomposition reaction of N2O5(g): For the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 → NO2 + NO3 (K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Indicate whether the following rate expression is acceptable: d[N2O5] = -k₁[N₂O₂] + K¸₁[NO₂][NO3] - K¸[NO₂]³ dtarrow_forwardIn a reaction of A + B to give C, another compound other than A, B or C may appear in the kinetic equation.arrow_forwardFor the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 →> NO₂+ NO3_(K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → → NO2 + O2 + NO (K2) NO + N2O5- NO2 + NO2 + NO2 (K3) d[N₂O5] __2k‚k₂[N2O5] Indicate whether the following rate expression is acceptable: dt k₁₁+ k₂arrow_forward
- Given the reaction R + Q → P, indicate the rate law with respect to R, with respect to P and with respect to P.arrow_forwardSteps and explanations. Also provide, if possible, ways to adress this kind of problems in general.arrow_forwardk₁ Given the reaction A B, indicate k-1 d[A] (A). the rate law with respect to A: (B). the rate law with respect to B: d[B] dt dtarrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning