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Concept explainers
(a)
Interpretation:The best synthetic routefor synthesis of methanolfrom simple alkane should be suggested and disadvantages of synthesis with
Concept introduction: The carbonyl bond is polar with the partial positive charge on carbon and partial negative charge on oxygen as illustrated below.
Grignard reagents are
Methyl bromide reacts with magnesium ether to give Grignard reagent. This Grignard methyl magnesium bromide on treatment with formaldehyde gives corresponding alcohol. The mechanistic pathway for the latter reaction is as follows:
The polar carbonyl bond breaks and the polar Grignard reagent attack at electron-deficient carbon. Finally with the hydrolysis and work up the alcohol is formed.
(b)
Interpretation: The best synthetic route for synthesis of ethanol from simple alkane should be suggested.
Concept introduction: Grignard reagents are alkyl magnesium halides obtained from treatment of haloalkane with magnesium in presence of dried ether conditions. These reagents are useful precursors for quick synthesis of variety of organic compounds For example, the reaction of Grignard reagent with aldehyde or ketone generates alcohol as illustrated below.
(c)
Interpretation: The best synthetic route for synthesis of
Concept introduction:Grignard reagents are alkyl magnesium halides obtained from treatment of haloalkane with magnesium in presence of dried ether conditions. These reagents are useful precursors for quick synthesis of variety of organic compounds For example, the reaction of Grignard reagent with aldehyde or ketone generates alcohol as illustrated below.
Methyl bromide reacts with magnesium in ether to give Grignard reagent. This Grignard methylmagnsium bromide on treatment with formaldehyde gives corresponding alcohol.
(d)
Interpretation: The best synthetic route for synthesis of
Concept introduction:Grignard reagents are alkyl magnesium halides obtained from treatment of haloalkane with magnesium in presence of dried ether conditions. These reagents are useful precursors for quick synthesis of variety of organic compounds For example, the reaction of Grignard reagent with aldehyde or ketone generates alcohol as illustrated below.
Methyl bromide reacts with magnesium ether to give Grignard reagent. This Grignard methyl magnesium bromide on treatment with formaldehyde gives corresponding alcohol.
(e)
Interpretation: The best synthetic route for synthesis of
Concept introduction:Grignard reagents are alkyl magnesium halides obtained from treatment of haloalkane with magnesium in presence of dried ether conditions. These reagents are useful precursors for quick synthesis of variety of organic compounds For example, the reaction of Grignard reagent with aldehyde or ketone generates alcohol as illustrated below.
Methyl bromide reacts with magnesium ether to give Grignard reagent. This Grignard methyl magnesium bromide on treatment with formaldehyde gives corresponding alcohol.
(f)
Interpretation: The best Synthetic route for synthesis of
Concept introduction:Grignard reagents are alkyl magnesium halides obtained from treatment of haloalkane with magnesium in presence of dried ether conditions. These reagents are useful precursors for quick synthesis of variety of organic compounds For example, the reaction of Grignard reagent with aldehyde or ketone generates alcohol as illustrated below.
Methyl bromide reacts with magnesium ether to give Grignard reagent. This Grignard methyl magnesium bromide on treatment with formaldehyde gives corresponding alcohol.
(g)
Interpretation: The best Synthetic route for synthesis of
Concept introduction:Grignard reagents are alkyl magnesium halides obtained from treatment of haloalkane with magnesium in presence of dried ether conditions. These reagents are useful precursors for quick synthesis of variety of organic compounds For example, the reaction of Grignard reagent with aldehyde or ketone generates alcohol as illustrated below.
Methyl bromide reacts with magnesium ether to give Grignard reagent. This Grignard methyl magnesium bromide on treatment with formaldehyde gives corresponding alcohol.
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Chapter 8 Solutions
ORGANIC CHEMISTRY (LL)-PACKAGE
- Explain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement? if the standard deviation is 0.01 and the propagated uncertainty is 0.03arrow_forwardPropagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 7.65±0.04 + 5.28±0.02 – 1.12±0.01 85.6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forwardExplain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement?arrow_forward
- Circle the compound in each pair where the indicated bond vibrates at higher frequency. WHY IS THIS? Provide thorough explanation to tie topic.arrow_forwardHow can you distinguish between each pair of compounds below using IR? Cite a bond and frequency that can be used to distinguish. Provide thorough steps and explanation.arrow_forwardPropagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 65±0.04 + 5.28±0.02 – 1.12±0.01 6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forward
- Match to correct spectrum and explain the bonds and frequencies used to tell what spectrum connected to the given option. Thanks.arrow_forwardDraw the virtual orbitals for the planar and pyramidal forms of CH3 and for the linear and bent forms of CH2arrow_forwardQ2: Draw the molecules based on the provided nomenclatures below: (2R,3S)-2-chloro-3-methylpentane: (2S, 2R)-2-hydroxyl-3,6-dimethylheptane:arrow_forward
- Q3: Describes the relationship (identical, constitutional isomers, enantiomers or diastereomers) of each pair of compounds below. ག H CH3 OH OH CH3 H3C OH OH OH ////////// C CH3 CH3 CH3 CH3 H3C CH 3 C/III..... Physics & Astronomy www.physics.northweste COOH H нош..... H 2 OH HO CH3 HOOC H CH3 CH3 CH3 Br. H H Br and H H H Harrow_forwardQ1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. OH HO CI Br H CI CI Br CI CI Xf x f g Br D OH Br Br H₂N R. IN Ill I -N S OMe D II H CO₂H 1/111 DuckDuckGarrow_forwardThese are synthesis questions. You need to show how the starting material can be converted into the product(s) shown. You may use any reactions we have learned. Show all the reagents you need. Show each molecule synthesized along the way and be sure to pay attention to the regiochemistry and stereochemistry preferences for each reaction. If a racemic molecule is made along the way, you need to draw both enantiomers and label the mixture as "racemic". All of the carbon atoms of the products must come from the starting material! ? H Harrow_forward
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