Interpretation: The electrical charge of an ionic compound needs to be explained.
Concept Introduction:Ionic compound is formed by the chemical combination of a metal and a non-metal. Here, metal tends to be electron-rich, and non-metal tends to be electron deficient. Thus, metals donate electron/s to form a positively charged ion or cation and non-metals accept electron/s to form a negatively charged ion or anion.
Answer to Problem 12LC
Ionic compounds are said to be electrically neutral or have zero electrical charges.
Explanation of Solution
In an ionic compound, metal and non-metal chemically combine. Here, the metal loses electrons, and non-metal gains electrons. The charge on the metal and non-metal depends on the number of electrons lost and gained respectively. Here, metal and non-metals are combined in a ratio such that the total charge is zero. For example, if metal M has a +2 charge and non-metal X has a -1 charge, both M and X combine in the ratio of 2:1 and form
Since metal and non-metal always combine in the ratio so the total charge of the compound is zero; thus, an ionic compound is always electrically neutral.
Thus, ionic compounds are said to be electrically neutral or have zero electrical charges.
Chapter 7 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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- For each of the following, indicate whether the arrow pushes are valid. Do we break any rules via the arrows? If not, indicate what is incorrect. Hint: Draw the product of the arrow and see if you still have a valid structure. a. b. N OH C. H N + H d. e. f. مه N COHarrow_forwardDecide which is the most acidic proton (H) in the following compounds. Which one can be removed most easily? a) Ha Нь b) Ha Нь c) CI CI Cl Ha Ньarrow_forwardProvide all of the possible resonanse structures for the following compounds. Indicate which is the major contributor when applicable. Show your arrow pushing. a) H+ O: b) c) : N :O : : 0 d) e) Оarrow_forward
- Draw e arrows between the following resonance structures: a) b) : 0: :0: c) :0: N t : 0: بار Narrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl Substitution will not occur at a significant rate. Explanation Check :☐ O-CH + Х Click and drag to start drawing a structure.arrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl C O Substitution will not occur at a significant rate. Explanation Check + O-CH3 Х Click and drag to start drawing a structure.arrow_forward
- ✓ aw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. C Cl HO–CH O Substitution will not occur at a significant rate. Explanation Check -3 ☐ : + D Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Cearrow_forwardPlease correct answer and don't used hand raitingarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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