
(a)
Interpretation: The group of nitrogen in the periodic table and the number of valance electrons present in it need to be determined.
Concept Introduction: In a periodic table, the group of an element can be determined from the
Nitrogen belongs to group 5A and the number of valance electrons is 5.
The given element is nitrogen. The atomic number of nitrogen atom is 7. The electronic configuration can be represented as follows:
Here, the number of electrons present in
Therefore, nitrogen belongs to group 5A, and the number of valance electrons is 5.
(b)
Interpretation: The group of lithium in the periodic table and the number of valance electrons present in it need to be determined.
Concept Introduction: In a periodic table, the group of an element can be determined from the atomic number and number of valence electrons present in its atom. There are 18 groups in a periodic table. Here, elements are arranged in such a way that group 1 has elements with 1 electron in the outermost shell, group 2 has elements with 2 electrons, and so on. The number of valance electrons can also be calculated from the electronic configuration of an atom of the element. Here, electrons present in the outermost shell are known as valance electrons.
Lithium belongs to group 1A and the number of valance electrons is 1.
The given element is lithium. The atomic number lithium is 3. The electronic configuration can be represented as follows:
Here, the number of electrons present in
Therefore, lithium belongs to group 1 and the number of valance electrons is 1.
(c)
Interpretation: The group of phosphorus in the periodic table and the number of valance electrons present in it need to be determined.
Concept Introduction: In a periodic table, the group of an element can be determined from the atomic number and number of valence electrons present in its atom. There are 18 groups in a periodic table. Here, elements are arranged in such a way that group 1 has elements with 1 electron in the outermost shell, group 2 has elements with 2 electrons, and so on. The number of valance electrons can also be calculated from the electronic configuration of an atom of the element. Here, electrons present in the outermost shell are known as valance electrons.
Phosphorus belongs to group 5A and the number of valance electrons is 5.
The given element is phosphorus. The atomic number of phosphorus is 15. The electronic configuration can be represented as follows:
Here, the number of electrons present in
Therefore, phosphorus belongs to group 5A and the number of valance electrons is 5.
(d)
Interpretation: The group of barium in the periodic table and the number of valance electrons present in it need to be determined.
Concept Introduction: In a periodic table, the group of an element can be determined from the atomic number and number of valence electrons present in its atom. There are 18 groups in a periodic table. Here, elements are arranged in such a way that group 1 has elements with 1 electron in the outermost shell, group 2 has elements with 2 electrons, and so on. The number of valance electrons can also be calculated from the electronic configuration of an atom of the element. Here, electrons present in the outermost shell are known as valance electrons.
Barium belongs to group 2A and the number of valance electrons is 2.
(e)
Interpretation: The group of bromine in the periodic table and the number of valance electrons present in it need to be determined.
Concept Introduction: In a periodic table, the group of an element can be determined from the atomic number and number of valence electrons present in its atom. There are 18 groups in a periodic table. Here, elements are arranged in such a way that group 1 has elements with 1 electron in the outermost shell, group 2 has elements with 2 electrons, and so on. The number of valance electrons can also be calculated from the electronic configuration of an atom of the element. Here, electrons present in the outermost shell are known as valance electrons.
Bromine belongs to group 7A and the number of valance electrons is 7.
The given element is bromine. The atomic number of the bromine atom is 35. The electronic configuration can be represented as follows:
Here, the number of electrons present in
Therefore, bromine belongs to group 17 and the number of valance electrons is 7.
(f)
Interpretation: The group of carbon in the periodic table and the number of valance electrons present in it need to be determined.
Concept Introduction: In a periodic table, the group of an element can be determined from the atomic number and number of valence electrons present in its atom. There are 18 groups in a periodic table. Here, elements are arranged in such a way that group 1 has elements with 1 electron in the outermost shell, group 2 has elements with 2 electrons, and so on. The number of valance electrons can also be calculated from the electronic configuration of an atom of the element. Here, electrons present in the outermost shell are known as valance electrons.
Carbon belongs to group 4A and the number of valance electrons is 4.
The given element is carbon. The atomic number of carbon atom is 6. The electronic configuration can be represented as follows:
Here, the number of electrons present in
Therefore, carbon belongs to group 4A and the number of valance electrons is 4.
Chapter 7 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- > Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forwardPredict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forward
- can someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forwardWhat would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactants in the following reaction: X + Y H+ two steps Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Х :arrow_forward
- I am struggling with the IUPAC (sys H Reply ☑Mark as Unreadarrow_forwardDon't used hand raiting and don't used Ai solution and correct answerarrow_forwardH R Part: 1/2 :CI: is a/an electrophile Part 2 of 2 Draw the skeletal structure of the product(s) for the Lewis acid-base reaction. Include lone pairs and formal charges (if applicable) on the structures. 4-7: H ö- H Skip Part Check X :C1: $ % L Fi Click and drag to start drawing a structure. MacBook Pro & ㅁ x G 0: P Add or increase positive formal cha Save For Later Submit ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





