
(a)
Interpretation: The electron dot structure of the potassium atom needs to be drawn.
Concept Introduction: Electron dot structures of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, a symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.
(a)

Answer to Problem 6LC
Explanation of Solution
The given atom is potassium. The element belongs to group 1 and the
The number of electrons present in the valance shell that is
Since the number of valance electrons present in potassium is 1, its electron dot structure can be represented as follows:
(b)
Interpretation: The electron dot structure of the carbon atom needs to be drawn.
Concept Introduction:Electron dot structures of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, a symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.
(b)

Answer to Problem 6LC
Explanation of Solution
The given atom is carbon. The element belongs to group 14 and the atomic number is 6. The electronic configuration is represented as follows:
The number of electrons present in the valance shell that is
Since the number of valance electrons present in carbon is 4, its electron dot structure can be represented as follows:
(c)
Interpretation: The electron dot structure of the magnesium atom needs to be drawn.
Concept Introduction:Electron dot structures of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, a symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.
(c)

Answer to Problem 6LC
Explanation of Solution
The given atom is magnesium. The element belongs to group 2 and the atomic number is 12. The electronic configuration is represented as follows:
The number of electrons present in the valance shell that is
Since the number of valance electrons present in magnesium is 2, its electron dot structure can be represented as follows:
(d)
Interpretation: The electron dot structure of the oxygen atom needs to be drawn.
Concept Introduction:Electron dot structures of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, a symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.
(d)

Answer to Problem 6LC
Explanation of Solution
The given atom is oxygen. The element belongs to group 16 or 6A and the atomic number is 8. The electronic configuration is represented as follows:
The number of electrons present in the valance shell that is
Since the number of valance electrons present in oxygen is 6, its electron dot structure can be represented as follows:
Chapter 7 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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- true or falsegiven these two equilibria with their equilibrium constants:H2(g) + CI2(l) ↔ 2HCI(g) K= 0.006 CI2(l) ↔ CI2(g) K= 0.30The equilibrium contstant for the following reaction is 1.8H2(g) + CI2 ↔ 2HCI(g)arrow_forwardI2(g) + CI2(g) ↔ 2ICIK for this reaction is 81.9. Find the equilibrium concentration of I2 if the inital concentration of I2 and CI2 are 0.010 Marrow_forwardtrue or false,the equilibrium constant for this reaction is 0.50.PCI5(g) ↔ PCI3(g) + CI2(g)Based on the above, the equilibrium constant for the following reaction is 0.25.2PCI5(g) ↔. 2PCI3(g) + 2CI2(g)arrow_forward
- true or false, using the following equilibrium, if carbon dioxide is added the equilibrium will shift toward the productsC(s) + CO2(g) ↔ 2CO(g)arrow_forward2S2O2/3- (aq) + I2 (aq) ---> S4O2/6- (aq) +2I- (aq) Experiment I2 (M) S2O3- (M) Initital Rate (M/s) 1 0.01 0.01 0.0004 2 0.01 0.02 0.0004 3 0.02 0.01 0.0008 Calculate the overall order for this reaction using the table data a) 3b) 0c) 2d) 1arrow_forwardthe decomposition of N2O5 is the first order with a half-life of 1.98 minutes. If the inital concentration of N2O5 is 0.200 M, what is the concentration after 6 minutes?a) 0.612 Mb) 0.035 Mc) 0.024 Md) 0.100 Marrow_forward
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