
Interpretation:
The given element from the given table needs to be identified.
Concept introduction:
Amount of energy needed to remove most loosely bound electron from isolated gaseous atom of elements in its lowest energy state to produce a cation is known as ionization energy.

Answer to Problem 89A
The element is sulfur.
Explanation of Solution
Period 3 elements are s-block elements and p-block elements. The elements can potentially lose six valence electrons in the given table of ionization energy. Element is unlikely to lose six valence electrons thus there is a large difference between fifth and sixth valence electron. This is because 6th electron is to be removed from 3s which become half filled after removal of 5 electrons and close to the nucleus. Sulfur has the potential to lose six valence electrons and it is period 3 elements. The electronic configuration of sulfur is
The electronic configuration of sulfur is
Chapter 6 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
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