Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 6, Problem 38A
Interpretation Introduction
Interpretation:
The group and period of the element with 117 protons needs to be determined. Whether it is a metal, non-metal or a metalloid needs to be determined.
Concept introduction:
In the periodic table, vertical rows are termed as groups and horizontal rows are termed as periods. There are 18 groups and 7 periods in the periodic table. From the electronic configuration of the element, its group and period can be known.
Expert Solution & Answer
Answer to Problem 38A
The period and group to which element of
Explanation of Solution
The element contains 117 protons that mean atomic number of the element is 117. So, electronic configuration of the element is
Conclusion
Element of atomic number 117 belongs to 7th period and 17 group and it is a metalloid.
Chapter 6 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
Ch. 6.1 - Prob. 1SSCCh. 6.1 - Prob. 2SSCCh. 6.1 - Prob. 3SSCCh. 6.1 - Prob. 4SSCCh. 6.1 - Prob. 5SSCCh. 6.1 - Prob. 6SSCCh. 6.1 - Prob. 7SSCCh. 6.2 - Prob. 8PPCh. 6.2 - Prob. 9PPCh. 6.2 - Prob. 10PP
Ch. 6.2 - Prob. 11SSCCh. 6.2 - Prob. 12SSCCh. 6.2 - Prob. 13SSCCh. 6.2 - Prob. 14SSCCh. 6.2 - Prob. 15SSCCh. 6.3 - Prob. 16PPCh. 6.3 - Prob. 17PPCh. 6.3 - Prob. 18PPCh. 6.3 - Prob. 19PPCh. 6.3 - Prob. 20SSCCh. 6.3 - Prob. 21SSCCh. 6.3 - Prob. 22SSCCh. 6.3 - Prob. 23SSCCh. 6.3 - Prob. 24SSCCh. 6 - Prob. 25ACh. 6 - Prob. 26ACh. 6 - Prob. 27ACh. 6 - Prob. 28ACh. 6 - Prob. 29ACh. 6 - Prob. 30ACh. 6 - Prob. 31ACh. 6 - Prob. 32ACh. 6 - Prob. 33ACh. 6 - Prob. 34ACh. 6 - Prob. 35ACh. 6 - Prob. 36ACh. 6 - Prob. 37ACh. 6 - Prob. 38ACh. 6 - Prob. 39ACh. 6 - Prob. 40ACh. 6 - Prob. 41ACh. 6 - Prob. 42ACh. 6 - Prob. 43ACh. 6 - Prob. 44ACh. 6 - Prob. 45ACh. 6 - Prob. 46ACh. 6 - Prob. 47ACh. 6 - Prob. 48ACh. 6 - Prob. 49ACh. 6 - Prob. 50ACh. 6 - Prob. 51ACh. 6 - Prob. 52ACh. 6 - Prob. 53ACh. 6 - Prob. 54ACh. 6 - Prob. 55ACh. 6 - Prob. 56ACh. 6 - Prob. 57ACh. 6 - Prob. 58ACh. 6 - Prob. 59ACh. 6 - Prob. 60ACh. 6 - Prob. 61ACh. 6 - Prob. 62ACh. 6 - Prob. 63ACh. 6 - Prob. 64ACh. 6 - Prob. 65ACh. 6 - Prob. 66ACh. 6 - Prob. 67ACh. 6 - Prob. 68ACh. 6 - Prob. 69ACh. 6 - Prob. 70ACh. 6 - Prob. 71ACh. 6 - Prob. 72ACh. 6 - Prob. 73ACh. 6 - Prob. 74ACh. 6 - Prob. 75ACh. 6 - Prob. 76ACh. 6 - Prob. 77ACh. 6 - Prob. 78ACh. 6 - Prob. 79ACh. 6 - Prob. 80ACh. 6 - Prob. 81ACh. 6 - Prob. 82ACh. 6 - Prob. 83ACh. 6 - Prob. 84ACh. 6 - Prob. 85ACh. 6 - Prob. 86ACh. 6 - Prob. 87ACh. 6 - Prob. 88ACh. 6 - Prob. 89ACh. 6 - Prob. 90ACh. 6 - Prob. 91ACh. 6 - Prob. 92ACh. 6 - Prob. 93ACh. 6 - Prob. 94ACh. 6 - Prob. 95ACh. 6 - Prob. 96ACh. 6 - Prob. 97ACh. 6 - Prob. 98ACh. 6 - Prob. 99ACh. 6 - Prob. 100ACh. 6 - Prob. 1STPCh. 6 - Prob. 2STPCh. 6 - Prob. 3STPCh. 6 - Prob. 4STPCh. 6 - Prob. 5STPCh. 6 - Prob. 6STPCh. 6 - Prob. 7STPCh. 6 - Prob. 8STPCh. 6 - Prob. 9STPCh. 6 - Prob. 10STPCh. 6 - Prob. 11STPCh. 6 - Prob. 12STPCh. 6 - Prob. 13STPCh. 6 - Prob. 14STPCh. 6 - Prob. 15STPCh. 6 - Prob. 16STPCh. 6 - Prob. 17STPCh. 6 - Prob. 18STPCh. 6 - Prob. 19STP
Additional Science Textbook Solutions
Find more solutions based on key concepts
Two parents plan to have three children. What is the probability that the children will be two girls and one bo...
Genetic Analysis: An Integrated Approach (3rd Edition)
58. Is each compound soluble or insoluble? For the soluble compounds, identify the ions present in solution.
a....
Introductory Chemistry (6th Edition)
1.3 Obtain a bottle of multivitamins and read the list of ingredients. What are four chemicals from the list?
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Use the key to classify each of the following described tissue types into one of the four major tissue categori...
Anatomy & Physiology (6th Edition)
Why is an endospore called a resting structure? Of what advantage is an endospore to a bacterial cell?
Microbiology: An Introduction
EVOLUTION CONNECTION The percentages of naturally occurring elements making up the human body (see Table 2.1) a...
Campbell Biology (11th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- A first order reaction is 46.0% complete at the end of 59.0 minutes. What is the value of k? What is the half-life for this reaction? HOW DO WE GET THERE? The integrated rate law will be used to determine the value of k. In [A] [A]。 = = -kt What is the value of [A] [A]。 when the reaction is 46.0% complete?arrow_forward3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)arrow_forward2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2arrow_forward
- 4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forwardThe following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward
- 1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward
- 3. Draw diagrams to represent the conjugation in these molecules. Draw two types of diagram: a. Show curly arrows linking at least two different ways of representing the molecule b. Indicate with dotted lines and partial charges (where necessary) the partial double bond (and charge) distribution H₂N* H₂N -NH2arrow_forwardQuestion 2 of 25 point Question Attempt 3 of Ulimited Draw the structure for 3-chloro-4-ethylheptane. Part 2 of 3 Click and drag to start drawing a structure. Draw the structure for 1-chloro-4-ethyl-3-lodooctane. Click and drag to start drawing a structure. X G X B c Part 3 of 30 Draw the structure for (R)-2-chlorobutane. Include the stereochemistry at all stereogenic centers. Check Click and drag to start drawing a structure. G X A 。 MacBook Pro G P Save For Later Submit Assignment Privacyarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
NEET Chemistry | Group 14 Carbon Family | Theory & Problem Solving | In English | Misostudy; Author: Misostudy;https://www.youtube.com/watch?v=enOGIrcHh54;License: Standard YouTube License, CC-BY