
(a)
Interpretation:
The group, period, and block in which [Kr] 5s24d1 is located in the periodic table needs to be determined.
Concept introduction:
A periodic table consists of groups and periods. The horizontal rows are termed as periods and the vertical rows are termed as groups. The elements with similar properties are placed together in a group.

Answer to Problem 48A
Yttrium (Yt) has the electronic configuration [Kr] 5s24d1. It is located in group 3 of the d-block and in period 5.
Explanation of Solution
[Kr] 5s24d1is the given configuration. This configuration is seen to be located in d-block in group 3 and in period 5 on the periodic table.
On the basis od the location of the group and the period we can say that the element is Yttrium (Yt).
(b)
Interpretation:
The group, period, and block in which[Ar] 4s23d10 4p3is located in the periodic table needs to be determined.
Concept introduction:
A periodic table consists of groups and periods. The horizontal rows are termed as periods and the vertical rows are termed as groups. The elements with similar properties are placed together in a group.
(b)

Answer to Problem 48A
Arsenic (As) has the electronic configuration [Ar] 4s23d10 4p3. It is located in group 15 of the p-block and in period 4.
Explanation of Solution
[Ar] 4s23d10 4p3is the given configuration. This configuration is seen to be located in p-block in group 15 and in period 4 on the periodic table.
On the basis of the location of the group and the period we can say that the element is Arsenic (Ar).
(c)
Interpretation:
The group, period, and block in which [He] 2s22p6is located in the periodic table needs to be determined.
Concept introduction:
A periodic table consists of groups and periods. The horizontal rows are termed as periods and the vertical rows are termed as groups. The elements with similar properties are placed together in a group.
(c)

Answer to Problem 48A
Neon (Ne) has the electronic configuration [He] 2s22p6. It is located in group 18 of the p-block and in period 2.
Explanation of Solution
[He] 2s22p6is the given configuration. This configuration is seen to be located in p-block in group 18 and in period 2 on the periodic table.
On the basis of the location of the group and the period we can say that the element is Neon (Ne).
(d)
Interpretation:
The group, period, and block in which [Ne] 3s23p1is located in the periodic table needs to be determined.
Concept introduction:
A periodic table consists of groups and periods. The horizontal rows are termed as periods and the vertical rows are termed as groups. The elements with similar properties are placed together in a group.
(d)

Answer to Problem 48A
Aluminium (Al) has the electronic configuration[Ne] 3s23p1. It is located in group 13 of the p-block and in period 3.
Explanation of Solution
[Ne] 3s23p1is the given configuration. This configuration is seen to be located in p-block in group 13 and in period 3 on the periodic table.
On the basis of the location of the group and the period we can say that the element is Aluminium (Al).
Chapter 6 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
Additional Science Textbook Solutions
Microbiology: An Introduction
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Organic Chemistry (8th Edition)
Anatomy & Physiology (6th Edition)
Microbiology with Diseases by Body System (5th Edition)
Chemistry: Structure and Properties (2nd Edition)
- Please EnCircle or Fill-In your Choice CLEARLY: 21. Please Sketch the intermediates for each step below. Draw the Product which would result from the following series of reactions. Name each Type of Rx: 1. Br2, FeBr3 2. Mg, ether 3. ethylene oxide 4. H₂O+ 5. PBr3 6. Mg, ether 7. 8. H3O+, heat (-H₂O 9. HF ?arrow_forwardCan I please get help with this question. All required information should be in data table.arrow_forwardesc For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. Major Product: Explanation Check C ☐ + X NaOH Br F1 F2 80 F3 F4 F5 F6 1 ! @ 2 3 $ 4 % 5 Q W LU E S D A F7 * C Click and dr drawing a 2025 McGraw Hill LLC. All Rights Reserv ►II F8 4 F9 6 7 8 9 R T Y U LL F G H Jarrow_forward
- Calculate equilibrium concentrations for the following reaction:N2 (g) + O2 (g) ⇋ 2 NO (g) Kc = 0.10 at 2273K initially [N2] = 0.200M; [O2] = 0.200arrow_forwardFor each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forwardThe following reaction is run in which the initial conditions include only methane (CH4) at a concentration of0.115 M. Once equilibrium was established, the concentration of acetylene (C2H2) was measured to be 0.035M. What is the value of the equilibrium constant, K?2 CH4 (g) ⇋ C2H2 (g) + 3 H2 (g)arrow_forward
- Calculate the equilibrium concentration of carbon dioxide for the following reaction:2 COF2 (g) ⇋ CF4 (g) + CO2 (g) Kc = 2.00 at 10.00 °C. at equilibrium [COF2] = 0.255M; [CF4] = 0.118Marrow_forwardIn a benzene derivative that has -CH2CH3, indicate how it can be substituted by -COOH.arrow_forwardIn a sulfonated derivative of benzene, indicate how -SO3H can be eliminated.arrow_forward
- What is the equilibrium expression (law of mass action) for the following reaction:CO2 (g) + H2O (l) ⇋ H+ (aq) + HCO3- (aq)arrow_forwardIndicate the compound resulting from adding NaOH cyclopentane-CH2-CHO.arrow_forwardUse the provided information to calculate Kc for the following reaction at 550 °C: H2(g) + CO2(g) ⇌ CO(g) + H2O(g) Kc = ?CoO(s) + CO(g) ⇌ Co(s) + CO2(g) Kc1 = 490CoO(s) + H2(g) ⇌ Co(s) + H2O(g) Kc2 = 67arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





