Biochemistry, The Molecular Basis of Life, 6th Edition
6th Edition
ISBN: 9780190259204
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 6, Problem 41RQ
Summary Introduction
To review:
The difference between the energy of the reaction and the activation energy of the reaction.
Introduction:
When a reaction takes place under normal conditions, the bonds of the reactants are broken down. They are rearranged to form the new bond, sesulting in the formation of new products. The energy released as the result of this breaking and formation of bonds is known as the energy of the reaction. Activation energy in the reactionis provided to accelerate the
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The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism
of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help
To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?
To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!
Chapter 6 Solutions
Biochemistry, The Molecular Basis of Life, 6th Edition
Ch. 6 - Prob. 1QCh. 6 - Prob. 2QCh. 6 - Prob. 3QCh. 6 - Prob. 4QCh. 6 - Prob. 5QCh. 6 - Prob. 6QCh. 6 - Prob. 7QCh. 6 - Prob. 8QCh. 6 - Prob. 9QCh. 6 - Prob. 1RQ
Ch. 6 - Prob. 2RQCh. 6 - Prob. 3RQCh. 6 - Prob. 4RQCh. 6 - Prob. 5RQCh. 6 - Prob. 6RQCh. 6 - Prob. 7RQCh. 6 - Prob. 8RQCh. 6 - Prob. 9RQCh. 6 - Prob. 10RQCh. 6 - Prob. 11RQCh. 6 - Prob. 12RQCh. 6 - Prob. 13RQCh. 6 - Prob. 14RQCh. 6 - Prob. 15RQCh. 6 - Prob. 16RQCh. 6 - Prob. 17RQCh. 6 - Prob. 18RQCh. 6 - Prob. 19RQCh. 6 - Prob. 20RQCh. 6 - Prob. 21RQCh. 6 - Prob. 22RQCh. 6 - Prob. 23RQCh. 6 - Prob. 24RQCh. 6 - Prob. 25RQCh. 6 - Prob. 26RQCh. 6 - Prob. 27RQCh. 6 - Prob. 28RQCh. 6 - Prob. 29RQCh. 6 - Prob. 30RQCh. 6 - Prob. 31RQCh. 6 - Prob. 32RQCh. 6 - Prob. 33RQCh. 6 - Prob. 34RQCh. 6 - Prob. 35RQCh. 6 - Prob. 36RQCh. 6 - Prob. 37RQCh. 6 - Prob. 38RQCh. 6 - Prob. 39RQCh. 6 - Prob. 40RQCh. 6 - Prob. 41RQCh. 6 - Prob. 42RQCh. 6 - Prob. 43FBCh. 6 - Prob. 44FBCh. 6 - Prob. 45FBCh. 6 - Prob. 46FBCh. 6 - Prob. 47FBCh. 6 - Prob. 48FBCh. 6 - Prob. 49FBCh. 6 - Prob. 50FBCh. 6 - Prob. 51FBCh. 6 - Prob. 52FBCh. 6 - Prob. 53SACh. 6 - Prob. 54SACh. 6 - Prob. 55SACh. 6 - Prob. 56SACh. 6 - Prob. 57SACh. 6 - Prob. 58TQCh. 6 - Prob. 59TQCh. 6 - Prob. 60TQCh. 6 - Prob. 61TQCh. 6 - Prob. 62TQCh. 6 - Prob. 63TQCh. 6 - Prob. 64TQCh. 6 - Prob. 65TQCh. 6 - Prob. 66TQCh. 6 - Prob. 67TQCh. 6 - Prob. 68TQCh. 6 - Prob. 69TQCh. 6 - Prob. 70TQCh. 6 - Prob. 71TQCh. 6 - Prob. 72TQCh. 6 - Prob. 73TQCh. 6 - Prob. 74TQCh. 6 - Prob. 75TQCh. 6 - Prob. 76TQCh. 6 - Prob. 77TQCh. 6 - Prob. 78TQCh. 6 - Prob. 79TQCh. 6 - Prob. 80TQCh. 6 - Prob. 81TQ
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