Organic Chemistry As a Second Language: Second Semester Topics

4th Edition

ISBN: 9781119110651

Author: David R. Klein

Publisher: WILEY

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Textbook Question

Chapter 4.1, Problem 4.2P

Consider the following reaction, in which an aromatic ring undergoes chlorination, rather than bromination:

Chapter 4.1, Problem 4.2P, Consider the following reaction, in which an aromatic ring undergoes chlorination, rather than

The mechanism is very similar to the mechanism for bromination. First, Cl₂ reacts with AlCl₃ to generate a complex that can serve as a source of Cl⁺. Draw a mechanism for formation of this complex.

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Chapter 3.10, Problem 3.55P

Chapter 4.1, Problem 4.3P

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Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10

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Chapter 4 Solutions

Organic Chemistry As a Second Language: Second Semester Topics

Ch. 4.1 - Consider the following reaction, in which an...Ch. 4.1 - Prob. 4.3P Ch. 4.1 - Aromatic rings will also undergo iodination when...Ch. 4.2 - In each of the following cases, identify the...Ch. 4.2 - In each of the following cases, identify the...Ch. 4.2 - In each of the following cases, identify the...Ch. 4.3 - Prob. 4.10P Ch. 4.3 - Prob. 4.11P Ch. 4.3 - Prob. 4.12P Ch. 4.3 - Prob. 4.13P

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