
Interpretation:
Products formed for the reaction have to be predicted. The given reaction is shown as,
Concept Introduction:
Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors.
- Strong deactivators: They are very strong electron withdrawing groups.
- Moderate deactivators: It contains a pi bond that is attached to a strong electronegative group.
- Weak deactivators: It consists of halogens.
Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho-para directing.
- Strong activators: It contains a lone pair next to the
aromatic ring. - Moderate activators: It has a lone pair next to the aromatic ring that can take part in the resonance outside the ring as well.
- Weak activators: It consists of alkyl groups.
Halogens are deactivators that are ortho-para directing.
Rules to identify the group that dominates the directing effects:
- Ortho-para directors will always dominate meta directors.
- Strong activators will always dominate weak activators
Friedel-Crafts Alkylation: This Lewis acid-catalyzed electrophilic aromatic replacement that allows the synthesis of alkylated products by means of the reaction of arenes through

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Chapter 4 Solutions
Organic Chemistry As a Second Language: Second Semester Topics
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- Draw the product of the E2 reaction shown below. Include the correct stereochemistry. Ignore any inorganic byproducts. + Br CH3 Q Strong Base Drawing Atoms, Bonds and Rings Charges Undo Reset H "Br H N Br. Remove Done .N. Drag To Panarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the product of this elementary step in an elimination mechanism. Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore byproducts. + Br: .. 8 0.01 M NaOH heat Drawing Q Atoms, Bonds and Rings Charges and Lone Pairs Draw or tap a new bond to see suggestions. Undo Reset Remove Done + Drag To Panarrow_forward+ Draw the product of the E2 reaction shown below. Include the correct stereochemistry. Ignore any inorganic byproducts. Ph CH2CH3 H H3C H Br DBN [૪] Drawing Atoms, Bonds and Rings H | OH Charges ―00 H. C | Undo Reset Br I Remove Done Drag To Pan +arrow_forward
- Reaction A Now the production A Œ In the product of reaction i 12 Dear the product of actionarrow_forwardMacmillan Learnin When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm-1. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 DEPT 135 200 160 120 80 40 0 Draw the unknown amide. 40 40 0arrow_forwardDraw the major product karmed when I reach with the epoxide. Use walge dah bonds, including hydrogen al alcach genic center, to show the chemistry of the product Beeldraw any hydrogen akams on coxygen where applicablearrow_forward
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