Products formed for the reaction have to be predicted. The given reaction is shown as, Concept Introduction: Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors. Strong deactivators: They are very strong electron withdrawing groups. Moderate deactivators: It contains a pi bond that is attached to a strong electronegative group. Weak deactivators: It consists of halogens. Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho-para directing. Strong activators: It contains a lone pair next to the aromatic ring. Moderate activators: It has a lone pair next to the aromatic ring that can take part in the resonance outside the ring as well. Weak activators: It consists of alkyl groups. Halogens are deactivators that are ortho-para directing. Rules to identify the group that dominates the directing effects: Ortho-para directors will always dominate meta directors. Strong activators will always dominate weak activators Friedel-Crafts Alkylation: This Lewis acid-catalyzed electrophilic aromatic replacement that allows the synthesis of alkylated products by means of the reaction of arenes through alkyl halides or alkenes.

Question

Want to see the full answer?

Answer 1

Question

Chapter 4.7, Problem 4.78P

Interpretation Introduction

Interpretation:

Products formed for the reaction have to be predicted. The given reaction is shown as,

Concept Introduction:

Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors.

Strong deactivators: They are very strong electron withdrawing groups.

Moderate deactivators: It contains a pi bond that is attached to a strong electronegative group.

Weak deactivators: It consists of halogens.

Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho-para directing.

Strong activators: It contains a lone pair next to the aromatic ring.

Moderate activators: It has a lone pair next to the aromatic ring that can take part in the resonance outside the ring as well.

Weak activators: It consists of alkyl groups.

Halogens are deactivators that are ortho-para directing.

Rules to identify the group that dominates the directing effects:

Ortho-para directors will always dominate meta directors.

Strong activators will always dominate weak activators

Friedel-Crafts Alkylation: This Lewis acid-catalyzed electrophilic aromatic replacement that allows the synthesis of alkylated products by means of the reaction of arenes through alkyl halides or alkenes.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

The structure of compound 1,3,5-trimethylbenzene (mesitylene) is given below. How many signals would you expect to find in the 'H NMR spectrum of 1,3,5-trimethylbenzene (mesitylene)? Check ×

1 How many signals do you expect in the 'H NMR spectrum for this molecule? CI CI Cl Write the answer in the table below. Also, in each of the drawing areas below is a copy of the molecule, with H atoms shown. In each copy, one of the H atoms is highlighted red. Highlight in red all other H atoms that would contribute to the same signal as the H already highlighted red. Note for advanced students: Remember, a multiplet is considered one signal in the 'H NMR spectrum. 1 Number of signals in the 'H NMR spectrum. ☐ For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional H atoms to highlight in top molecule For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at…

wrtie the balanced equation and find the E° when the following half- reactions are combined Zn2+(aq) + 2e---> Zn(s) E°= -0.763V Ag+(aq) + e---> Ag (s) E°=+0.799V