
Interpretation:
Products formed for the reaction have to be predicted. The given reaction is shown as,
Concept Introduction:
Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors.
- Strong deactivators: They are very strong electron withdrawing groups.
- Moderate deactivators: It contains a pi bond that is attached to a strong electronegative group.
- Weak deactivators: It consists of halogens.
Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho-para directing.
- Strong activators: It contains a lone pair next to the
aromatic ring. - Moderate activators: It has a lone pair next to the aromatic ring that can take part in the resonance outside the ring as well.
- Weak activators: It consists of alkyl groups.
Halogens are deactivators that are ortho-para directing.
Rules to identify the group that dominates the directing effects:
- Ortho-para directors will always dominate meta directors.
- Strong activators will always dominate weak activators
Friedel-Crafts Acylation: This Lewis acid-catalyzed electrophilic aromatic substitution is the reaction between arenes and acyl chlorides or anhydrides for the synthesis of monoacylated compound. The products are deactivated, as well as do not undergo a second substitution.

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Chapter 4 Solutions
Organic Chemistry As a Second Language: Second Semester Topics
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- ΌΗ 1) V2 CO 3 or Nalt In منهarrow_forward6. The equilibrium constant for the reaction 2 HBr (g) → H2(g) + Br2(g) Can be expressed by the empirical formula 11790 K In K-6.375 + 0.6415 In(T K-¹) - T Use this formula to determine A,H as a function of temperature. Calculate A,-H at 25 °C and at 100 °C.arrow_forward3. Nitrosyl chloride, NOCI, decomposes according to 2 NOCI (g) → 2 NO(g) + Cl2(g) Assuming that we start with no moles of NOCl (g) and no NO(g) or Cl2(g), derive an expression for Kp in terms of the equilibrium value of the extent of reaction, Seq, and the pressure, P. Given that K₂ = 2.00 × 10-4, calculate Seq/ of 29/no when P = 0.080 bar. What is the new value по ƒª/ at equilibrium when P = 0.160 bar? Is this result in accord with Le Châtelier's Principle?arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning

