Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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Chapter 4, Problem 4.8MCQ
An ac resistance is higher than a dc resistance.
- True
- False
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Chapter 4 Solutions
Power System Analysis and Design (MindTap Course List)
Ch. 4 - ACSR stands for Aluminum-clad steel conductor...Ch. 4 - Overhead transmission-line conductors are bare...Ch. 4 - Alumoweld is an aluminum-clad steel conductor....Ch. 4 - EHV lines often have more than one conductor per...Ch. 4 - Shield wires located above the phase conductors...Ch. 4 - Conductor spacings, types, and sizes do have an...Ch. 4 - A circle with diameter Din.=1000Dmil=dmil has an...Ch. 4 - An ac resistance is higher than a dc resistance....Ch. 4 - Prob. 4.9MCQCh. 4 - Transmission line conductance is usually neglected...
Ch. 4 - Prob. 4.11MCQCh. 4 - Prob. 4.12MCQCh. 4 - For a single-phase, two-wire line consisting of...Ch. 4 - For a three-phase three-wire line consisting of...Ch. 4 - For a balanced three-phase positive-sequence...Ch. 4 - A stranded conductor is an example of a composite...Ch. 4 - lnAk=lnAk True FalseCh. 4 - Prob. 4.18MCQCh. 4 - Expand 6k=13m=12Dkm.Ch. 4 - Prob. 4.20MCQCh. 4 - For a single-phase two-conductor line with...Ch. 4 - In a three-phase line, in order to avoid unequal...Ch. 4 - For a completely transposed three-phase line...Ch. 4 - Prob. 4.24MCQCh. 4 - Does bundling reduce the series reactance of the...Ch. 4 - Does r=e14r=0.788r, which comes in calculation of...Ch. 4 - In terms of line-to-line capacitance, the...Ch. 4 - For either single-phase two-wire line or balanced...Ch. 4 - Prob. 4.29MCQCh. 4 - Prob. 4.30MCQCh. 4 - Prob. 4.31MCQCh. 4 - Prob. 4.32MCQCh. 4 - Prob. 4.33MCQCh. 4 - Prob. 4.34MCQCh. 4 - The affect of the earth plane is to slightly...Ch. 4 - When the electric field strength at a conductor...Ch. 4 - Prob. 4.37MCQCh. 4 - Prob. 4.38MCQCh. 4 - Considering two parallel three-phase circuits that...Ch. 4 - The Aluminum Electrical Conductor Handbook lists a...Ch. 4 - The temperature dependence of resistance is also...Ch. 4 - A transmission-line cable with a length of 2 km...Ch. 4 - One thousand circular mils or 1 kcmil is sometimes...Ch. 4 - A 60-Hz, 765-kV, three-phase overhead transmission...Ch. 4 - A three-phase overhead transmission line is...Ch. 4 - If the per-phase line loss in a 70-km-long...Ch. 4 - A 60-Hz, single-phase two-wire overhead line has...Ch. 4 - Prob. 4.9PCh. 4 - A 60-Hz, three-phase three-wire overhead line has...Ch. 4 - Prob. 4.11PCh. 4 - Find the inductive reactance per mile of a...Ch. 4 - A single-phase overhead transmission line consists...Ch. 4 - Prob. 4.14PCh. 4 - Find the GMR of a stranded conductor consisting of...Ch. 4 - Prob. 4.16PCh. 4 - Determine the GMR of each of the unconventional...Ch. 4 - A 230-kV, 60-Hz, three-phase completely transposed...Ch. 4 - Prob. 4.19PCh. 4 - Calculate the inductive reactance in /km of a...Ch. 4 - Rework Problem 4.20 if the bundled line has (a)...Ch. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - For the overhead line of configuration shown in...Ch. 4 - Prob. 4.26PCh. 4 - Figure 4.34 shows double-circuit conductors'...Ch. 4 - For the case of double-circuit, bundle-conductor...Ch. 4 - Prob. 4.29PCh. 4 - Figure 4.37 shows the conductor configuration of a...Ch. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.38PCh. 4 - Calculate the capacitance-to-neutral in F/m and...Ch. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Three ACSR Drake conductors are used for a...Ch. 4 - Consider the line of Problem 4.25. Calculate the...Ch. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - The capacitance of a single-circuit, three-phase...Ch. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Approximately how many physical transmission...Ch. 4 - Prob. BCSQCh. 4 - Prob. CCSQCh. 4 - Prob. DCSQ
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- A certain signal f(t) has the following PSD (assume 12 load): Sp (w) = new + 8(w) - 1.5) + (w + 1.5)] (a) What is the mean power in the bandwidth w≤2 rad/see? (b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec? Paress(w) dw 2ㅈ -arrow_forward(75 Marks) JA signal (t) is bond 7)(t)(t) and f(t), are band-limited to 1.2 kHz each. These signals are to be limited to 9.6 kHz, and three other signals transmitted by means of time-division multiplexing. Set up scheme for accomplishing this multiplexing requirement, with each signal sampled at its Nyquist rate. What must be the speed of the commutator (the output but ram-k bit/sec)? the minimum band width? (25 Marks)arrow_forwardDraw the digital modulation outputs, ASK Amplitude Shift Keying) FSK (Frequency Shift Keying) and PSK (Phase Shift Keying). For baseband and carriet frequency as shown 101 wwwwwwwwwwww 010 BASESAND basband CARRIER Carralarrow_forward
- please show full working. I've included the solutionarrow_forwardcan you please show working and steps. The answer is 8kohms.arrow_forwardPSD A certain signal f(t) has the following PSD (assume 12 load): | Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)] (a) What is the mean power in the bandwidth w≤ 1 rad/sec? (b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec? (c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec? (d) What is the total mean power in (t)? Pav= + 2T SfLw) dw - SALW)arrow_forward
- An AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forward
- Can you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forwardA. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forwardFind Io using Mesh analysisarrow_forward
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