Explanation of Solution
Method to find the middle node of doubly linked list:
This method moves right from head is assigned to middle node and at the same time moves left from tail is assigned to partner node.
- If the middle and partner node is equal, then return the middle node.
- If middle node is just next node of partner node, then it even number of elements. So, return the previous node of middle node.
Program:
//Define the middle() method
private Node<E> middle()
{
//Check whether the list is empty
if (size == 0)
//Throw an exception
throw new IllegalStateException("List must not be empty");
//Assign the next node of head to middle Node
Node<E> middleNode = head−>next;
//Assign the previous node of tail to partner Node
Node<E> partnerNode = tail−>prev;
/*Loop executes until the middle node and partner node is not equal and next node of middle node and partner node is not equal. */
while (middleNode != partnerNode && middleNode−>next != partnerNode)
{
//Assign next node of middle node to middle node
middleNode = middleNode.getNext();
/*Assign previous node of partner node to partner node...
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Data Structures and Algorithms in Java
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