
Explanation of Solution
The algorithm to split the two half of circularly linked list “L” is given below:
Algorithm:
Input: circularly linked list “L” contains even number of nodes.
Output: Split the “L” into two half of circularly linked list “L” and “M”.
split(L):
//Create circularly linked list "M"
CircularlyLinkedList M = new CircularlyLinkedList()
/*Create node for temporary use and assign tail of list "L" into it. */
Node temp = L.tail;
//Loop executes until the half of size of list "L"
for i less than half of "L" size, then
/*Get next node of tail and assign it into "temp" node. */
temp = temp.getNext();
/*Get the next node of "temp" node and assign it into tail of "M" list. */
M.tail = temp.getNext();
/*Set the next node of "temp" node as the tail of list "L". */
temp.setNext(L.tail);
//Loop executes until the half of size of list "L"
for i less than half of "L" size, then
/*Get next node of tail and assign it into "temp" node...

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Chapter 3 Solutions
Data Structures and Algorithms in Java
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