(a)
Interpretation:
The geometrical structure of
Concept introduction:
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
The molecules with considering the domains of type
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
According to VSEPR theory,
Figure 1
(b)
Interpretation:
The geometrical structure of
Concept introduction:
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
The molecules with considering the domains of type
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
According to VSEPR theory,
Figure 1
(c)
Interpretation:
The geometrical structure of
Concept introduction:
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
The molecules with considering the domains of type
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
According to VSEPR theory,
Figure 1
(d)
Interpretation:
The geometrical structure of
Concept introduction:
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
The molecules with considering the domains of type
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
According to VSEPR theory,
Figure 1
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Chapter 19 Solutions
General Chemistry: Atoms First
- Thallium forms the compound TlI₃. What is the apparentoxidation state of Tl in this compound? Given that the anion is I₃⁻, what is the actual oxidation state of Tl? Draw the shape ofthe anion, giving its VSEPR class and bond angles. Propose areason why the compound does not exist as (Tl³⁺)(I⁻)₃.arrow_forwardDescribe the molecular structure of each of the following molecules or ions listed. (a) PH3(b) PH4+(c) P2H4(d) PO43−arrow_forward(c) Suggest how the following boron species could be prepared, showing any intermediates. -B(OH)2 B(OH)2arrow_forward
- (i) Interhalogen compounds are more reactive than halogens exceptF2. Why?(ii) Give one important use of ClF3.arrow_forwardWrite the Lewis structure for each of the following species,describe its geometry, and indicate the oxidation state ofthe nitrogen: (a) NH4+, (b) NO2- , (c) N2O, (d) NO2.arrow_forwardWrite a balanced chemical equation for the reaction that occurswhen (a) titanium metal reacts with O21g2; (b) silver(I)oxide decomposes into silver metal and oxygen gas whenheated; (c) propanol, C3H7OH1l2 burns in air; (d) methyltert-butyl ether, C5H12O1l2, burns in air.arrow_forward
- (i) How does O3react with lead sulphide? Write chemical equation.(ii) What happens when SO2is passed in acidified KMnO4solution?(iii) SO2 behaves with lime water similar to CO2.arrow_forwardBorazine, (BH)3(NH)3, is an analog of C6H6, benzene. It canbe prepared from the reaction of diborane with ammonia,with hydrogen as another product; or from lithium borohydrideand ammonium chloride, with lithium chlorideand hydrogen as the other products. (a) Write balancedchemical equations for the production of borazine usingboth synthetic methods. (b) Draw the Lewis dot structureof borazine. (c) How many grams of borazine can be preparedfrom 2.00 L of ammonia at STP, assuming diborane isin excess?arrow_forwardHow many moles of (CH3)3N would need to be added to 459.2 mL of a 0.25 M solution of (CH3)3NHCL to produce a solution with a pH equal to 9.21?arrow_forward
- The pH of a 0.2 M solution of CuSO4 is 4.0. Write chemical equations to explain why a solution of this salt is neither basic [from the reaction of SO42-(aq) with water] nor neutral, but acidic.arrow_forwardWhat is the oxidation state of the C atoms in C6H12O3?arrow_forwardPredict the products of each of the following reactions and then balance the chemical equations.(a) Fe is heated in an atmosphere of steam.(b) NaOH is added to a solution of Fe(NO3)3.(c) FeSO4 is added to an acidic solution of KMnO4.(d) Fe is added to a dilute solution of H2SO4.(e) A solution of Fe(NO3)2 and HNO3 is allowed to stand in air.(f) FeCO3 is added to a solution of HClO4.(g) Fe is heated in air.arrow_forward
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