
Concept explainers
Interpretation:
Correct option has to be chosen for the given compound considering the classification of the amide.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Organic compounds contain heteroatom also. Some of them are nitrogen, sulfur, oxygen etc. Nitrogen containing organic compounds are of two important types and they are
One of the
Amides are also classified as primary, secondary, and tertiary amide.
Primary amide is the one that has a nitrogen atom that is bonded to two hydrogen atoms. Primary amides are also known as unsubstituted amides.
Secondary amide is the one that has a nitrogen atom that is bonded to one hydrogen atom and one alkyl (or aryl) group. Secondary amides are also known as monosubstituted amides.
Tertiary amide is the one that has a nitrogen atom that is bonded to two alkyl (or aryl) groups. Tertiary amides are also known as disubstituted amides.

Want to see the full answer?
Check out a sample textbook solution
Chapter 17 Solutions
General, Organic, and Biological Chemistry Seventh Edition
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,

