(a)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
(b)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
(c)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
(d)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
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Chapter 17 Solutions
General, Organic, and Biological Chemistry Seventh Edition
- Give the structure(s) of the product(s) for the reactions below, and be sure to indicate any relative stereochemistry (you can assume that each of the Diels-Alder reactions will proceed with endo selectivity). Draw out relevant enantiomer(s) if they are expected to form. If no reaction is expected to occur under the indicated conditions, then write "no reaction" or NR, and explain why you would expect nothing to occur. If more than one product is formed, please indicate which one will be the major product or if they will be formed in equal amounts. In all cases, equimolar amounts of both components/reagents are present unless indicated otherwise .arrow_forwardCalculate the residence time of strontium (Sr2+) in the world ocean, given that the average concentration of strontium in the world’s rivers is approximately 0.87 µmol L-1 (5 pts).arrow_forwardA package contains 1.33lbs of ground round. If it contains 29% fat, how many grams of fat are in the ground? arrow_forward
- How is the resonance structure formed to make the following reaction product. Please hand draw the arrows showing how the electrons move to the correct position. Do not use an AI answer. Please draw it yourself or don't bother.arrow_forwardPart II Calculate λ max of the following compounds using wood ward- Fiecer rules a) b) c) d) e) OH OH dissolved in dioxane Br Br dissolved in methanol. NH₂ OCH 3 OHarrow_forward6. Match each of the lettered items in the column on the left with the most appropriate numbered item(s) in the column on the right. Some of the numbered items may be used more than once and some not at all. a. Z = 37 1. b. Mn 2. C. Pr element in period 5 and group 14 element in period 5 and group 15 d. S e. [Rn] 7s¹ f. d block metal 3. highest metallic character of all the elements 4. paramagnetic with 5 unpaired electrons 5. 4f36s2 6. isoelectronic with Ca²+ cation 7. an alkaline metal 8. an f-block elementarrow_forward
- Draw all formal charges on the structures below as is and draw 1 resonance structure that is more stable.arrow_forwardPart II. xiao isolated a compound TAD (Ca H 10 N₂) from tobacco and obtained its IR spectrum. Xiao proposed a chemical structure shown below: % Transmittance 4000 3500 3000 2500 2000 Wavenumber (cm-1) 1500 1000 (a) Explain why her proposed structure is inconsistent with the IR spectrum obtained (b) TAD exists as a tautomer of the structure xiao proposed. Draw the structure and explain why it is more compatible with the obtained spectrum. (C) what is the possible source for the fairly intense signal at 1621cm1arrow_forwardAE>AE₁ (Y/N) AE=AE₁ (Y/N) AEarrow_forwardTreatment of 2-phenylpropan-2-amine with methyl 2,4-dibromobutanoate in the presence of a nonnucleophilic base, R3N, involves two successive SN2 reactions and gives compound A. ? NH2 Br Br Propose a structural formula for compound A. You do not have to explicitly draw H atoms. You do not have to consider stereochemistry. In cases where there is more than one answer, just draw one. R3N C14H19NO2 + 2 R3NH*Br Aarrow_forwardCorrectly name this compound using the IUPAC naming system by sorting the components into the correct order. Br IN Ν Harrow_forwardHow is the radical intermediate for this structure formed? Can you please draw arrows from the first radical to the resonance form that would result in this product? I'm lost.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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