The Ksp expression for Ca(OH) 2 should be written. Concept Introduction: Solubility product constant: The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant. The equilibrium constant of more soluble ionic compound is given by Ksp and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound. M m X x (s) ⇌ mM n+ (aq) + xX y- (aq) K sp = [M n+ ] m ×[X y- ] x
The Ksp expression for Ca(OH) 2 should be written. Concept Introduction: Solubility product constant: The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant. The equilibrium constant of more soluble ionic compound is given by Ksp and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound. M m X x (s) ⇌ mM n+ (aq) + xX y- (aq) K sp = [M n+ ] m ×[X y- ] x
Solution Summary: The author explains that the equilibrium constant of a more soluble ionic compound in water is known as solubility product constant.
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by Ksp and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound.
MmXx(s)⇌ mMn+(aq) + xXy-(aq)Ksp = [Mn+]m×[Xy-]x
(b)
Interpretation Introduction
Interpretation:
The balanced net ionic equation for the dissolution of Ag3PO4 and its Ksp expression should be written.
Concept Introduction:
Solubility product constant:
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by Ksp and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound.
MmXx(s)⇌ mMn+(aq) + xXy-(aq)Ksp = [Mn+]m×[Xy-]x
(c)
Interpretation Introduction
Interpretation:
The balanced net ionic equation for the dissolution of BaCO3 and its Ksp expression should be written.
Concept Introduction:
Solubility product constant:
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by Ksp and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound.
MmXx(s)⇌ mMn+(aq) + xXy-(aq)Ksp = [Mn+]m×[Xy-]x
(d)
Interpretation Introduction
Interpretation:
The balanced net ionic equation for the dissolution of Ca5(PO4)3OH and its Ksp expression should be written.
Concept Introduction:
Solubility product constant:
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by Ksp and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound.
What is the [OH⁻] of a 1.80 M solution of pyridine (C₅H₅N, Kb = 1.70 × 10⁻⁹)?
What is the percent ionization in a 0.260 M solution of formic acid (HCOOH) (Ka = 1.78 × 10⁻⁴)?
Determine the pH of solution of HC3H5O2 By constructing an ICE table writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HC3H5O2 is 1.3 x 10-5
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