General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Chapter 15, Problem 15.109SP
(a)
Interpretation Introduction
Interpretation:
The net ionic equation for the given reaction should be written and its equilibrium constant should be calculated.
Concept Introduction:
Balanced equation: The total number of atoms or ions that are present in reactant and product side of the equation is equal means equation is known as balanced equation.
Net ionic equation: Only the species, which are involving in product formation is present in the equation is known as net ionic equation.
The net ionic equation is derived from cancelling of spectator ions in ionic equation.
Equilibrium constant: At equilibrium the ratio of products to reactants (each raised to the power corresponding to its
For a general reaction,
(b)
Interpretation Introduction
Interpretation:
The net ionic equation for the given reaction should be written and its equilibrium constant should be calculated.
Concept Introduction:
Balanced equation: The total number of atoms or ions that are present in reactant and product side of the equation is equal means equation is known as balanced equation.
Net ionic equation: Only the species, which are involving in product formation is present in the equation is known as net ionic equation.
The net ionic equation is derived from cancelling of spectator ions in ionic equation.
Equilibrium constant: At equilibrium the ratio of products to reactants (each raised to the power corresponding to its stoichiometric coefficient) has a constant value, K
For a general reaction,
(c)
Interpretation Introduction
Interpretation:
The net ionic equation for the given reaction should be written and its equilibrium constant should be calculated.
Concept Introduction:
Balanced equation: The total number of atoms or ions that are present in reactant and product side of the equation is equal means equation is known as balanced equation.
Net ionic equation: Only the species, which are involving in product formation is present in the equation is known as net ionic equation.
The net ionic equation is derived from cancelling of spectator ions in ionic equation.
Equilibrium constant: At equilibrium the ratio of products to reactants (each raised to the power corresponding to its stoichiometric coefficient) has a constant value, K
For a general reaction,
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of the five salts listed below, which has the highest concentration of its cation in water? assume that all salt solutions are saturated and that the ions do not undergo any additional reactions in water. (a) lead(ii) chromate, ksp = 2.8 × 10–13 (b) cobalt(ii) hydroxide, ksp = 1.3 × 10–15 (c) cobalt(ii) sulfide, ksp = 5 × 10–22 (d) chromium(iii) hydroxide, ksp = 1.6 × 10–30 (e) silver sulfide, ksp = 6 × 10–51
A 250-mL buffer solution contains 0.0510 mole of KH2PO4 and 0.0875 mole of K2HPO4.
(a) Calculate the molar concentrations of H2PO4–and HPO42–, respectively, in thesolution.
(b) What is the pH of the solution? (H2PO4– has Ka = 6.2 x 10–8)
(c) Write a net ionic equation for the buffering reaction against a strong acid by this buffer.
(d) If 0.012 mole of hydrochloric acid (HCl) is added to the solution, create a reaction table to show the buffering reaction and calculate the molar concentration of H2PO4–and HPO42–, respectively, in the resulting solution after the buffering reaction.
(e) What is the pH of the resulting solution?
Which of the following pairs of solution would you use to prepare a buffer with pH = 7.45?
(A) Acetic acid + sodium acetate; (CH3CO2H has Ka = 1.8 x 10–5)
(B) Sodium dihydrogen phosphate + sodium hydrogen phosphate; (H2PO4– has Ka = 6.2 x 10–8)
(C) Ammonium chloride + ammonia; (NH3 has Kb = 1.8 x 10–5)
(D) Sodium hydrogen carbonate + sodium carbonate; (HCO3– has Ka = 5.6 x 10–11)
Chapter 15 Solutions
General Chemistry: Atoms First
Ch. 15.1 - Write balanced net ionic equations for the...Ch. 15.1 - Write balanced net ionic equations for the...Ch. 15.2 - Calculate the concentrations of all species...Ch. 15.2 - Calculate the pH in a solution prepared by...Ch. 15.2 - Prob. 15.5CPCh. 15.3 - The following pictures represent solutions that...Ch. 15.3 - Calculate the pH of 0.100 L of a buffer solution...Ch. 15.3 - Calculate the change in pH when 0.002 mol of HNO3...Ch. 15.4 - Use the HendersonHasselbalch equation to calculate...Ch. 15.4 - Prob. 15.10P
Ch. 15.4 - Suppose you are performing an experiment that...Ch. 15.4 - Prob. 15.12PCh. 15.6 - A 40.0 mL volume of 0.100 M HCl is titrated with...Ch. 15.6 - A 40.0 mL volume of 0.100 M NaOH is titrated with...Ch. 15.7 - The following pictures represent solutions at...Ch. 15.7 - Consider the titration of 100.0 mL of 0.016 M HOCl...Ch. 15.7 - The following acid-base indicators change color in...Ch. 15.9 - Assume that 40.0 mL of 0.0800 M H2SO3 (Ka1 = 1.5 ...Ch. 15.9 - Assume that 40.0 mL of a 0.0250 M solution of the...Ch. 15.10 - Write the equilibrium-constant expression for Ksp...Ch. 15.11 - A saturated solution of Ca3(PO4)2 has [Ca2+] =...Ch. 15.11 - Prob. 15.22PCh. 15.11 - Which has the greater molar solubility: AgCl with...Ch. 15.11 - Prob. 15.24CPCh. 15.12 - Calculate the molar solubility of MgF2 in 0.10 M...Ch. 15.12 - Which of the following compounds are more soluble...Ch. 15.12 - In an excess of NH3(aq), Cu2+ ion forms a deep...Ch. 15.12 - Silver bromide dissolves in aqueous sodium...Ch. 15.13 - Prob. 15.29PCh. 15.13 - Will a precipitate form on mixing 25 mL of 1.0 ...Ch. 15.14 - Prob. 15.31PCh. 15.15 - Prob. 15.32PCh. 15 - The following pictures represent solutions that...Ch. 15 - The following pictures represent solutions that...Ch. 15 - The strong acid HA is mixed with an equal molar...Ch. 15 - The following pictures represent solutions at...Ch. 15 - The following pictures represent solutions at...Ch. 15 - The following pictures represent solutions at...Ch. 15 - Prob. 15.40CPCh. 15 - Prob. 15.41CPCh. 15 - Prob. 15.42CPCh. 15 - Prob. 15.43CPCh. 15 - Is the pH greater than, equal to, or less than 7...Ch. 15 - Prob. 15.45SPCh. 15 - Which of the following mixtures has the higher pH?...Ch. 15 - Which of the following mixtures has the lower pH?...Ch. 15 - Phenol (C6H5OH, Ka = 1.3 1010) is a weak acid...Ch. 15 - Aniline (C6H5NH2, Kb = 4.3 1010) is a weak base...Ch. 15 - The equilibrium constant Kn for the neutralization...Ch. 15 - The equilibrium constant Kn for the neutralization...Ch. 15 - Prob. 15.52SPCh. 15 - Does the pH increase, decrease, or remain the same...Ch. 15 - Prob. 15.54SPCh. 15 - Calculate the pH of a solution prepared by mixing...Ch. 15 - Prob. 15.56SPCh. 15 - The pH of a solution of NH3 and NH4Br is 8.90....Ch. 15 - Prob. 15.58SPCh. 15 - Prob. 15.59SPCh. 15 - Prob. 15.60SPCh. 15 - Which of the following gives a buffer solution...Ch. 15 - Prob. 15.62SPCh. 15 - Prob. 15.63SPCh. 15 - Calculate the pH of a buffer solution that is 0.20...Ch. 15 - Prob. 15.65SPCh. 15 - Calculate the pH of 0.250 L of a 0.36 M formic...Ch. 15 - Calculate the pH of0.375 L of a 0.18 M acetic...Ch. 15 - Prob. 15.68SPCh. 15 - Use the HendersonHasselbalch equation to calculate...Ch. 15 - Prob. 15.70SPCh. 15 - Give a recipe for preparing a CH3CO2HCH3CO2Na...Ch. 15 - Prob. 15.72SPCh. 15 - Prob. 15.73SPCh. 15 - What is the Ka of the amino acid leucine if it is...Ch. 15 - Prob. 15.75SPCh. 15 - Prob. 15.76SPCh. 15 - Make a rough plot of pH versus milliliters of acid...Ch. 15 - Prob. 15.78SPCh. 15 - Consider the titration of 50.0 mL of 0.116 M NaOH...Ch. 15 - Consider the titration of 40.0 mL of 0.250 M HF...Ch. 15 - A 100.0 mL sample of 0.100 M methylamine (CH3NH2,...Ch. 15 - Prob. 15.82SPCh. 15 - Consider the titration of 25.0 mL of 0.0200 M...Ch. 15 - Prob. 15.84SPCh. 15 - The equivalence point was reached in titrations of...Ch. 15 - Prob. 15.86SPCh. 15 - What is the pH at the equivalence point for the...Ch. 15 - Prob. 15.88SPCh. 15 - Prob. 15.89SPCh. 15 - Prob. 15.90SPCh. 15 - Prob. 15.91SPCh. 15 - Prob. 15.92SPCh. 15 - Prob. 15.93SPCh. 15 - Prob. 15.94SPCh. 15 - Prob. 15.95SPCh. 15 - Prob. 15.96SPCh. 15 - Prob. 15.97SPCh. 15 - Use Le Chteliers principle to explain the...Ch. 15 - Use Le Chteliers principle to predict whether the...Ch. 15 - Calculate the molar solubility of PbCrO4 in:...Ch. 15 - Calculate the molar solubility of SrF2 in:...Ch. 15 - Which of the following compounds are more soluble...Ch. 15 - Which of the following compounds are more soluble...Ch. 15 - Prob. 15.104SPCh. 15 - Is the solubility of Fe(OH)3 increased, decreased,...Ch. 15 - Prob. 15.106SPCh. 15 - Prob. 15.107SPCh. 15 - Prob. 15.108SPCh. 15 - Prob. 15.109SPCh. 15 - Calculate the molar solubility of AgI in: (a)Pure...Ch. 15 - Calculate the molar solubility of Cr(OH)3 in 0.50...Ch. 15 - What compound, if any, will precipitate when 80 mL...Ch. 15 - Prob. 15.113SPCh. 15 - Prob. 15.114SPCh. 15 - In qualitative analysis, Al3+ and Mg2+ are...Ch. 15 - Prob. 15.116SPCh. 15 - Can Co2+ be separated from Zn2+ by bubbling H2S...Ch. 15 - Prob. 15.118SPCh. 15 - Prob. 15.119SPCh. 15 - Prob. 15.120SPCh. 15 - Give a method for separating the following pairs...Ch. 15 - Assume that you have three white solids: NaCl,...Ch. 15 - On the same graph, sketch pH titration curves for...Ch. 15 - Prob. 15.124CHPCh. 15 - Prob. 15.125CHPCh. 15 - A saturated solution of Mg(OH)2 in water has pH =...Ch. 15 - Prob. 15.128CHPCh. 15 - In qualitative analysis, Ag+, Hg22+, and Pb2+ are...Ch. 15 - Calculate the molar solubility of MnS in a 0.30 M...Ch. 15 - Prob. 15.131CHPCh. 15 - Prob. 15.132CHPCh. 15 - Prob. 15.133CHPCh. 15 - Prob. 15.134CHPCh. 15 - Prob. 15.135CHPCh. 15 - A 100.0 mL sample of a solution that is 0.100 M in...Ch. 15 - A 0.0100 mol sample of solid Cd(OH)2 (Ksp = 5.3 ...Ch. 15 - Zinc hydroxide, Zn(OH)2 (Ksp = 4.1 1017), is...Ch. 15 - Prob. 15.139CHPCh. 15 - Prob. 15.140MPCh. 15 - Ethylenediamine (NH2CH2CH2NH2, abbreviated en) is...Ch. 15 - A 40.0 mL sample of a mixture of HCl and H3PO4 was...Ch. 15 - A 1.000 L sample of HCl gas at 25 C and 732.0 mm...Ch. 15 - Prob. 15.144MPCh. 15 - Consider the reaction that occurs on mixing 50.0...Ch. 15 - In qualitative analysis, Ca2+ and Ba2+ are...Ch. 15 - A railroad tank car derails and spills 36 tons of...Ch. 15 - Prob. 15.148MP
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