After addition of 3 .0 mL of 1 .0 M KOH in the titration of 25 .0 mL of 0 .125 M HCl with 0 .100 M KOH , pH of the solution should be calculated. Concept introduction: Acid-base neutralization reaction: The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction because of where neutralization is occur. pH: pH is a logarithmic expression to express a solution is acidic, basic or neutral. The pH scale has values between 1 and 14 and on which 7 is neutral, below 7 values are more acidic in nature and above 7 values are more basic in nature. pH = -log 10 [H + ]
After addition of 3 .0 mL of 1 .0 M KOH in the titration of 25 .0 mL of 0 .125 M HCl with 0 .100 M KOH , pH of the solution should be calculated. Concept introduction: Acid-base neutralization reaction: The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction because of where neutralization is occur. pH: pH is a logarithmic expression to express a solution is acidic, basic or neutral. The pH scale has values between 1 and 14 and on which 7 is neutral, below 7 values are more acidic in nature and above 7 values are more basic in nature. pH = -log 10 [H + ]
Solution Summary: The author explains the acid-base neutralization reaction. The pH is a logarithmic expression to express that the solution is acidic, basic or neutral.
After addition of 3.0 mLof1.0 M KOH in the titration of 25.0 mL of 0.125 MHCl with 0.100 MKOH, pH of the solution should be calculated.
Concept introduction:
Acid-base neutralization reaction:
The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction because of where neutralization is occur.
pH:
pH is a logarithmic expression to express a solution is acidic, basic or neutral. The pH scale has values between 1 and 14 and on which 7 is neutral, below 7 values are more acidic in nature and above 7 values are more basic in nature.
pH=-log10[H+]
(b)
Interpretation Introduction
Interpretation:
After addition of 20.0 mLof0.10 M KOH in the titration of 25.0 mL of 0.125 MHCl with 0.100 MKOH, pH of the solution should be calculated.
Concept introduction:
Acid-base neutralization reaction:
The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction because of where neutralization is occur.
pH:
pH is a logarithmic expression to express a solution is acidic, basic or neutral. The pH scale has values between 1 and 14 and on which 7 is neutral, below 7 values are more acidic in nature and above 7 values are more basic in nature.
pH=-log10[H+]
(c)
Interpretation Introduction
Interpretation:
After addition of 65.0 mLof1.0 M KOH in the titration of 25.0 mL of 0.125 MHCl with 0.100 MKOH, pH of the solution should be calculated.
Concept introduction:
Acid-base neutralization reaction:
The aqueous solution of acid react with aqueous solution of base to produce soluble salt with water in known as acid-base neutralization reaction because of where neutralization is occur.
pH:
pH is a logarithmic expression to express a solution is acidic, basic or neutral. The pH scale has values between 1 and 14 and on which 7 is neutral, below 7 values are more acidic in nature and above 7 values are more basic in nature.
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
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Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
The following equations represent the formation of compound MX. What is the AH for the
electron affinity of X (g)?
X₂ (g) → 2X (g)
M (s) → M (g)
M (g)
M (g) + e-
AH = 60 kJ/mol
AH = 22 kJ/mol
X (g) + e-X (g)
M* (g) +X (g) → MX (s)
AH = 118 kJ/mol
AH = ?
AH = -190 kJ/mol
AH = -100 kJ/mol
a)
-80 kJ
b)
-30 kJ
c)
-20 kJ
d)
20 kJ
e)
156 kJ
A covalent bond is the result of the
a)
b)
c)
d)
e)
overlap of two half-filled s orbitals
overlap of a half-filled s orbital and a half-filled p orbital
overlap of two half-filled p orbitals along their axes
parallel overlap of two half-filled parallel p orbitals
all of the above
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