Concept explainers
(a)
Interpretation:
The change in solubility of
Le Chatelier's principle:
Le Chatelier's principle states that if a system in equilibrium gets disturbed due to modification of concentration, temperature, volume, and pressure, then it reset to counteract the effect of disturbance.
The concentrations of reactant and product are equal in equilibrium
Solubility product constant:
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by
Molar solubility:
Molar solubility (S) is given as solubility in moles per litre.
(b)
Interpretation:
The change in solubility of
Concept Introduction:
Le Chatelier's principle:
Le Chatelier's principle states that if a system in equilibrium gets disturbed due to modification of concentration, temperature, volume, and pressure, then it reset to counteract the effect of disturbance.
The concentrations of reactant and product are equal in equilibrium chemical reaction. The effect of concentration, temperature and external pressure makes a change in equilibrium. To counteract this, the chemical reaction is shifted to reactant or product side to attain equilibrium.
Solubility product constant:
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by
Molar solubility:
Molar solubility (S) is given as solubility in moles per litre.
(c)
Interpretation:
The change in solubility of
Concept Introduction:
Le Chatelier's principle:
Le Chatelier's principle states that if a system in equilibrium gets disturbed due to modification of concentration, temperature, volume, and pressure, then it reset to counteract the effect of disturbance.
The concentrations of reactant and product are equal in equilibrium chemical reaction. The effect of concentration, temperature and external pressure makes a change in equilibrium. To counteract this, the chemical reaction is shifted to reactant or product side to attain equilibrium.
Solubility product constant:
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by
Molar solubility:
Molar solubility (S) is given as solubility in moles per litre.
Want to see the full answer?
Check out a sample textbook solutionChapter 15 Solutions
General Chemistry: Atoms First
- A volume of 50 mL of 1.8 M NH3 is mixed with an equal volume of a solution containing 0.95 g of MgCl2. What mass of NH4Cl must be added to the resulting solution to prevent the precipitation of Mg(OH)2?arrow_forwardConsider the reaction BaF2(s)+SO42(aq)BaSO4(s)+2 F(aq) (a) Calculate K for the reaction. (b) Will BaSO4 precipitate if Na2SO4 is added to a saturated solution of BaF2?arrow_forward4. The value of the solubility product, K for calcium hydroxide, Ca(OH), is 5.5 x 10, at25"C. (a) Write the K expression for calcium hydroxide. (b) What is the mass of Ca(OH), in 500 ml of a saturated solution at 25°C? (c) What is the pH of the solution in (b)? (d) If 1.0 mole of OH Is added to the solution in (b), what will be the resulting Ca concentration? Assume that the volume of the solution does not change.arrow_forward
- A buffer solution was prepared that contained 0.60 M hydrogen fluoride, HF (Ka = 7.2 x 104) and 1.00M potassium fluoride, KF. The total volume was 250 mL. (a) What ions and molecules are present in the solution? List them in order of decreasing concentration: Decreasing order of Concentration (b) What is the pH of the buffer solution described above? (c) What is the pH of 100. mL of the buffer solution if you add 100. x 10-3 g of NaOH? Assume negligible change in volume. (USEFUL INFORMATION: MM NaOH = 39.997 g mol-1)arrow_forwardA buffer is prepared by adding 5.0 g of ammonia, NH3, and 20.0 g of ammonium chloride, NH4Cl, to enough water to form 2.50 L of solution. (a) What is the pH of the buffer? (b) Write the complete ionic equation for the reaction that occurs when a few drops of nitric acid are added to the buffer. (c) Write the complete ionic equation for the reaction that occurs when a few drops of potassium hydroxide solution are added to the buffer.arrow_forwardA buffer solution contains 0.50 M acetic acid (CH3COOH; Ka = 1.8 x 10–5) and 0.35 M sodium acetate, NaCH3CO2. What is the pH of the solution? (A) 4.59 (B) 4.90 (C) 2.29 (D) 2.52arrow_forward
- 31. (a) Calculate the pH of a mixture containing 0.1 M propanoic acid (CH3CH₂COOH) and 0.050 M sodium propanoate (CH3CH₂COONa) (b) Determine the change in pH that occurs when 0.15 mol solid NaOH is added to 1.00 litre of the buffered solution. 32. (a) Calculate the pH of a buffer solution produced by adding 3.28 g of sodium ethanoate to 1 dm3 of 0.01 M of ethanoic acid (Ka = 1.84x 10-5 at 300K) (b) calculate the pH of this buffer if 10 cm3 of 0.1 M HCl are now addedarrow_forwardPredict the solubility change (increase, decrease, or no change) of the following compounds. Explain your choice in details. (a) Cu(OH)2 when adding HCl solution (b) AgI when adding HCl solution (c) PbCl2 when adding KCl solutionarrow_forward1. 50.00ml of 2.000M ammonium nitrate is titrated with 0.800M NaOH. (a) What is the pH at the equivalence point? (b) What is the pH of the solution at the initial point? (c) What is the volume of NaOH required to react with all of the acid? (d) What is the pH of the solution after the addition of 175.00ml of the base? (e) What is the pH of the solution halfway to the equivalence point?arrow_forward
- Please explain.arrow_forwardA solution is 0.085 M in Pb2 + and 0.025 M in Ag+. (a) If selective precipitation is to be achieved using NaCl, what minimum concentration of NaCl do you need to begin to precipitate the ion that precipitates first? (b) What is the concentration of each ion left in solution at the point where the second ion begins to precipitate?arrow_forwardA 35.00-mL solution of 0.2500 M HF is titrated with a standardized 0.1762 M solution of NaOH at 25 °C. (a) What is the pH of the HF solution before titrant is added? (b) How many milliliters of titrant are required to reach the equivalence point? mL (c) What is the pH at 0.50 mL before the equivalence point? (d) What is the pH at the equivalence point? (e) What is the pH at 0.50 mL after the equivalence point?arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning