Chapter 15, Problem 15.91SP

(a)

Interpretation Introduction

Interpretation:

The $\text{Ksp}$ vale for ${\text{Ca}}_3{{\text{(PO}}_4)}_2$ solution should be calculate that has ${\text{[Ca}}^{\text{2+}}{\text{] = [PO}}_{\text{4}}{}^{\text{3-}}\text{]}$ $\text{= 2}\text{.9}\times {\text{10}}^{\text{-7}}\text{M}$.

Concept Introduction:

Solubility product constant:

The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.

The equilibrium constant of more soluble ionic compound is given by $\text{Ksp}$ and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound.

$\begin{array}{l}{\text{M}}_{\text{m}}{\text{X}}_{\text{x}}{}_{\text{(s)}}\stackrel{}{\rightleftharpoons }{\text{ mM}}^{\text{n+}}{}_{\text{(aq)}}{\text{ + xX}}^{\text{y-}}{}_{\text{(aq)}}\\ \\ {\text{K}}_{\text{sp}}{\text{ = [M}}^{\text{n+}}{\text{]}}^{\text{m}}{\text{×[X}}^{\text{y-}}{\text{]}}^{\text{x}}\end{array}$

(b)

Interpretation Introduction

Interpretation:

The concentration of ${\text{[Ca}}^{+}\text{]}$ in ${\text{Ca}}_3{{\text{(PO}}_4)}_2$ solution should be calculate that has ${\text{[PO}}_{\text{4}}{}^{\text{3-}}\text{] = 0}\text{.010 M}$.

Concept Introduction:

Solubility product constant:

The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.

The equilibrium constant of more soluble ionic compound is given by $\text{Ksp}$ and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound.

$\begin{array}{l}{\text{M}}_{\text{m}}{\text{X}}_{\text{x}}{}_{\text{(s)}}\stackrel{}{\rightleftharpoons }{\text{ mM}}^{\text{n+}}{}_{\text{(aq)}}{\text{ + xX}}^{\text{y-}}{}_{\text{(aq)}}\\ \\ {\text{K}}_{\text{sp}}{\text{ = [M}}^{\text{n+}}{\text{]}}^{\text{m}}{\text{×[X}}^{\text{y-}}{\text{]}}^{\text{x}}\end{array}$

(c)

Interpretation Introduction

Interpretation:

The concentration of ${\text{[PO}}_4{}^{\text{3-}}\text{]}$ in ${\text{Ca}}_3{{\text{(PO}}_4)}_2$ solution should be calculate that has ${\text{[Ca}}^{2+}\text{] = 0}\text{.010 M}$.

Concept Introduction:

Solubility product constant:

The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.

The equilibrium constant of more soluble ionic compound is given by $\text{Ksp}$ and it is expressed by product of multiplication of number of each ion present in the compound rise to the power of number respective ion present in the compound to give a maximum solubility of the compound.

$\begin{array}{l}{\text{M}}_{\text{m}}{\text{X}}_{\text{x}}{}_{\text{(s)}}\stackrel{}{\rightleftharpoons }{\text{ mM}}^{\text{n+}}{}_{\text{(aq)}}{\text{ + xX}}^{\text{y-}}{}_{\text{(aq)}}\\ \\ {\text{K}}_{\text{sp}}{\text{ = [M}}^{\text{n+}}{\text{]}}^{\text{m}}{\text{×[X}}^{\text{y-}}{\text{]}}^{\text{x}}\end{array}$