Chapter 15, Problem 15.132CHP

Interpretation Introduction

Interpretation:

The $\text{pH}$ of the solution which is prepared by mixing $\text{60}\text{.0 mL}$ of $\text{1}{\text{.00 M H}}_{\text{3}}{\text{PO}}_{\text{4}}$ and $\text{1}\text{.00 L}$ of $\text{0}\text{.100 M LiOH}$ should be calculated.

Concept Introduction:

$\text{pH:}$

The negative logarithm of hydrogen ion ${\text{(H}}^{+})$ concentration of solution is given as $\text{pH}$.

$\text{pH}\text{=}{\text{-log}}_{\text{10}}{\text{[H}}^{\text{+}}\text{]}$

Henderson-Hasselbach Equation:

$\text{pH}$ of the buffer solution is given by below equation,

$\text{pH}\text{=}{\text{pK}}_{\text{a}}\text{+log}\frac{\text{[Base]}}{\text{[Acid]}}$