Concept explainers
Videos
Interpretation:
From, the given information, aufbau principle, needs to be explained.
Concept introduction:
Aufbau principle: According to Aufbau principle, the electron filling in different orbital takes place from lower to higher energy level. That is electron in lowest energy level fills before the highest energy level.
Answer to Problem 14STP
From the given electron configuration for silicon that is 1s2 2s2 2p63s2 3p2, it can be understand that is electron in lowest energy level fills before the highest energy level that is the Aufbau principle, which states that electron filling in different orbital takes place from lower to higher energy level.
Aufbau principle: According to Aufbau principle, the electron filling in different orbital takes place from lower to higher energy level. That is electron in lowest energy level fills before the highest energy level.
From the given electron configuration for silicon that is 1s2 2s2 2p63s2 3p2, it can be understand that is electron in lowest energy level fills before the highest energy level.
Energy of a level can be drived from its n+l value, which is lower for 1+0=1, than 2s which 2+0 and 2p which is 2+1.
That is electron first fill in 1s orbital then is 2s, which is higher in energy than 1s, after that electron fills in 2p which is higher in energy than 2s, then electron fills in 3s, which is higher in energy than 2p, after that electron fills in 3p which is higher in energy than 3s.
Explanation of Solution
Aufbau principle: According to Aufbau principle, the electron filling in different orbital takes place from lower to higher energy level. That is electron in lowest energy level fills before the highest energy level.
From the given electron configuration for silicon that is 1s2 2s2 2p63s2 3p2, it can be understand that is electron in lowest energy level fills before the highest energy level.
Energy of a level can be drived from its n+l value, which is lower for 1+0=1, than 2s which 2+0 and 2p which is 2+1.
That is electron first fill in 1s orbital then is 2s, which is higher in energy than 1s, after that electron fills in 2p which is higher in energy than 2s, then electron fills in 3s, which is higher in energy than 2p, after that electron fills in 3p which is higher in energy than 3s.
Chapter 14 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
Additional Science Textbook Solutions
Campbell Biology: Concepts & Connections (9th Edition)
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Cosmic Perspective Fundamentals
Human Physiology: An Integrated Approach (8th Edition)
Campbell Biology (11th Edition)
Applications and Investigations in Earth Science (9th Edition)
- 4) Answer the following exercise with curved arrows indicating who is a nucleophile or Who is the electrophile? 2.44 Predict the structure of the product formed in the reaction of the organic base pyridine with the organic acid acetic acid, and use curved arrows to indicate the direction of electron flow. 7 H3C OH N Pyridine Acetic acidarrow_forwardUsing the data provided please help me answer this question. Determine the concentration of the iron(Ill) salicylate in the unknown directly from to graph and from the best fit trend-line (least squares analysis) of the graph that yielded a straight line.arrow_forwardPlease help me figure out what the slope is and how to calculate the half life Using the data provided.arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the structure of the missing reactants, intermediates, or products in the following mechanism. Include all lone pairs. Ignore stereochemistry. Ignore inorganic byproducts. H Br2 (1 equiv) H- Select to Draw Starting Alkene Draw Major Product I I H2O 四: ⑦.. Q Draw Major Charged Intermediate Iarrow_forwardNH (aq)+CNO (aq) → CO(NH2)2(s) Experiment [NH4] (M) [CNO] (M) Initial rate (M/s) 1 0.014 0.02 0.002 23 0.028 0.02 0.008 0.014 0.01 0.001 Calculate the rate contant for this reaction using the data provided in the table.arrow_forward2CIO2 + 20H-1 CIO31 + CIO2 + H2O Experiment [CIO2], M [OH-1], M 1 0.0500 0.100 23 2 0.100 0.100 3 0.100 0.0500 Initial Rate, M/s 0.0575 0.230 0.115 ... Given this date, calculate the overall order of this reaction.arrow_forward
- 2 3 .(be)_[Ɔ+(be)_OI ← (b²)_IƆO+ (be)_I Experiment [1-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 0.000069 4 0.0025 0.0025 0.000140 Calculate the rate constant of this reaction using the table data.arrow_forward1 2 3 4 I(aq) +OCl(aq) → IO¯¯(aq) + Cl¯(aq) Experiment [I-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 Calculate the overall order of this reaction using the table data. 0.0025 0.000069 0.0025 0.000140arrow_forwardH2O2(aq) +3 I¯(aq) +2 H+(aq) → 13(aq) +2 H₂O(l)· ••• Experiment [H2 O2]o (M) [I]o (M) [H+]。 (M) Initial rate (M/s) 1 0.15 0.15 0.05 0.00012 234 0.15 0.3 0.05 0.00024 0.3 0.15 0.05 0.00024 0.15 0.15 0.1 0.00048 Calculate the overall order of this reaction using the table data.arrow_forward
- The U. S. Environmental Protection Agency (EPA) sets limits on healthful levels of air pollutants. The maximum level that the EPA considers safe for lead air pollution is 1.5 μg/m³ Part A If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lung volume of 5.40 L.) ΜΕ ΑΣΦ = 2.35 1013 ? atoms ! Check your rounding. Your final answer should be rounded to 2 significant figures in the last step. No credit lost. Try again.arrow_forwardY= - 0.039 (14.01) + 0.7949arrow_forwardSuppose 1.76 g of magnesium acetate (Mg (CH3CO2)2) are dissolved in 140. mL of water. Find the composition of the resulting electrolyte solution. In particular, list the chemical symbols (including any charge) of each dissolved ion in the table below. List only one ion per row. mEq Then, calculate the concentration of each ion in dwrite the concentration in the second column of each row. Be sure you round your answers to the L correct number of significant digits. ion Add Row mEq L x 5arrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY