Chapter 14, Problem 89A

Interpretation Introduction

Interpretation:

The solubility of a gas is to be calculated.

Concept introduction:

Solubility: Solubility can be expressed as maximum amount of solute that can dissolve in a known amount of solvent at a given temperature and pressure.

Henry’s Law: The solubility of a gas in liquid is directly proportional to the pressure of the gas above the liquid at a certain temperature.

Answer to Problem 89A

The solubility of a gas is 1.08 gm/litre.

Explanation of Solution

Given information:

${\mathrm{S}}_1=0.54\mathrm{gm}/litre$

${\mathrm{P}}_1=1.5\mathrm{atm}$

$\begin{array}{c}{P}_2=1.5\times 2atm\\ =3atm\end{array}$

The expression of Henry’s Law is $\frac{S_1}{P_1}=\frac{S_2}{P_2}$

The solubility of a gas is S₁ at P₁ pressure and S₂ at pressure P₂.

As the pressure is doubled.

$\begin{array}{c}\frac{S_1}{P_1}=\frac{S_2}{P_2}\\ S_2=\frac{S_1\times P_2}{P_1}\\ S_2=\frac{0.54gm/litre\times 3.0atm}{1.5atm}=1.08gm/litre\end{array}$

So, the solubility of the gas is 1.08 gm/litre.