Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
Question
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Chapter 14, Problem 120A
Interpretation Introduction

Interpretation:

The required volume of the stock solution and theboiling pointof the new solution have to be calculated.

Concept introduction:

For electrolyte solutes, the elevation of the boiling point is directly proportional to molality of the solution.

Boiling point elevation ΔTb=i×Kb×m

Where,

∆ Tb = Elevation of boiling point = the boiling point difference between a solution and the pure solvent

i = Van’t Hoff factor = for strong electrolyte ‘i’ is equal to number of dissociate ions.

Kb = the molal boiling point elevation constant

m = molality of the solution

Molality: Molality is defined as the number of moles of solute perkg of the solvent.

Molality of the solution=Numberofmolesof the solute Mass of the solvent(inKg)

Molarity: Molarity is defined as the number of moles of solute present in one litre of the solution In expression, Molarity of the solution=Numberofmolesof the solute Volume of the solution(inlitre)

Numberofmolesofsolute=MassofthesoluteMolecularweightofthesolute

Expert Solution & Answer
Check Mark

Answer to Problem 120A

The required volume of the stock solution is 302 mL and theboiling pointof the new solutionis 100.1 °C.

Explanation of Solution

Molarity of the solution=Numberofmolesof the solute Volume of the solution(inlitre)

Data given: Mass of KBr = 135.2 gm

Volume of the solution = 2.3 L

NumberofmolesofKBr=MassofKBrMolecularweightofKBr=135.2gm119gm/mol=1.14mol

Molarity of KBr solution=Numberofmolesof KBr Volume of the solution(inlitre)=1.14mole 2.3litre=0.496M

            M1V1= M2V2Stock solution = Diluted solution

Data given:

M1 = molarity of the stock solution = 0.496 M

M2 = molarity of the diluted solution = 0.1 M

V2 = volume of diluted solution = 1.5 L = 1500 mL

Volume of the stock solution = V1=M2V2M1V1=0.1M×1500mL0.496M=302mL

ΔTb=i×Kb×m

Molality of the new solution = m = 0.10

As, 1 L of water = 1 kg of water

‘i’ for KBr solution = 2

ΔTb=2×0.512°C/m×0.1m=0.1°C

So, theboiling pointof the new solution = 100 °C + 0.1 °C = 100.1°C.

Chapter 14 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 14.2 - Prob. 11PPCh. 14.2 - Prob. 12PPCh. 14.2 - Prob. 13PPCh. 14.2 - Prob. 14PPCh. 14.2 - Prob. 15PPCh. 14.2 - Prob. 16PPCh. 14.2 - Prob. 17PPCh. 14.2 - Prob. 18PPCh. 14.2 - Prob. 19PPCh. 14.2 - Prob. 20PPCh. 14.2 - Prob. 21PPCh. 14.2 - Prob. 22PPCh. 14.2 - Prob. 23PPCh. 14.2 - Prob. 24PPCh. 14.2 - Prob. 25PPCh. 14.2 - Prob. 26PPCh. 14.2 - Prob. 27PPCh. 14.2 - Prob. 28PPCh. 14.2 - Prob. 29PPCh. 14.2 - Prob. 30PPCh. 14.2 - Prob. 31SSCCh. 14.2 - Prob. 32SSCCh. 14.2 - Prob. 33SSCCh. 14.2 - Prob. 34SSCCh. 14.2 - Prob. 35SSCCh. 14.3 - Prob. 36PPCh. 14.3 - Prob. 37PPCh. 14.3 - Prob. 38PPCh. 14.3 - Prob. 39SSCCh. 14.3 - Prob. 40SSCCh. 14.3 - Prob. 41SSCCh. 14.3 - Prob. 42SSCCh. 14.3 - Prob. 43SSCCh. 14.3 - Prob. 44SSCCh. 14.4 - Prob. 45PPCh. 14.4 - Prob. 46PPCh. 14.4 - Prob. 47PPCh. 14.4 - Prob. 48SSCCh. 14.4 - Prob. 49SSCCh. 14.4 - Prob. 50SSCCh. 14.4 - Prob. 51SSCCh. 14.4 - Prob. 52SSCCh. 14.4 - Prob. 53SSCCh. 14 - Prob. 54ACh. 14 - What is the difference between a solute and a...Ch. 14 - Prob. 56ACh. 14 - Prob. 57ACh. 14 - Prob. 58ACh. 14 - Prob. 59ACh. 14 - Prob. 60ACh. 14 - Prob. 61ACh. 14 - Prob. 62ACh. 14 - Prob. 63ACh. 14 - Prob. 64ACh. 14 - How do 0.5M and 2.0M aqueous solutions of NaCl...Ch. 14 - Prob. 66ACh. 14 - Prob. 67ACh. 14 - Prob. 68ACh. 14 - Prob. 69ACh. 14 - Prob. 70ACh. 14 - Prob. 71ACh. 14 - Prob. 72ACh. 14 - Prob. 73ACh. 14 - How much CaCl2 , in grams, is needed to make 2.0 L...Ch. 14 - Stock solutions of HCl with various molarities are...Ch. 14 - Prob. 76ACh. 14 - Prob. 77ACh. 14 - Prob. 78ACh. 14 - If you dilute 20.0 mL of a 3.5M solution to...Ch. 14 - Prob. 80ACh. 14 - Prob. 81ACh. 14 - Prob. 82ACh. 14 - Prob. 83ACh. 14 - What is the mole fraction of H 2 S O 4 in a...Ch. 14 - Prob. 85ACh. 14 - Prob. 86ACh. 14 - Prob. 87ACh. 14 - Prob. 88ACh. 14 - Prob. 89ACh. 14 - Prob. 90ACh. 14 - Prob. 91ACh. 14 - Prob. 92ACh. 14 - Prob. 93ACh. 14 - Prob. 94ACh. 14 - Prob. 95ACh. 14 - Prob. 96ACh. 14 - Prob. 97ACh. 14 - Prob. 98ACh. 14 - Prob. 99ACh. 14 - In the lab, you dissolve 179 g of MgCl2 into1.00 L...Ch. 14 - Cooking A cook prepares a solution for boiling by...Ch. 14 - Prob. 102ACh. 14 - Ice Cream A rock salt (NaCl), ice, and water...Ch. 14 - Apply your knowledge of polarity and solubility...Ch. 14 - Prob. 105ACh. 14 - Which solute has the greatest effect on the...Ch. 14 - Study Table 14.4. Analyze solubility and...Ch. 14 - Prob. 108ACh. 14 - If you prepared a saturated aqueous solution of...Ch. 14 - How many grams of calcium nitrate (Ca(NO3)2)...Ch. 14 - Prob. 111ACh. 14 - Prob. 112ACh. 14 - Prob. 113ACh. 14 - Prob. 114ACh. 14 - Infer Dehydration occurs when more fluid is lost...Ch. 14 - Graph Table 14.10 shows solubility data that was...Ch. 14 - Design an Experiment You are given a sample of a...Ch. 14 - Compare Which of the following solutions has...Ch. 14 - Prob. 119ACh. 14 - Prob. 120ACh. 14 - Prob. 121ACh. 14 - Prob. 122ACh. 14 - Prob. 123ACh. 14 - Prob. 124ACh. 14 - Prob. 125ACh. 14 - Prob. 126ACh. 14 - Prob. 127ACh. 14 - Prob. 128ACh. 14 - Prob. 129ACh. 14 - Prob. 1STPCh. 14 - Prob. 2STPCh. 14 - Prob. 3STPCh. 14 - Prob. 4STPCh. 14 - Prob. 5STPCh. 14 - Prob. 6STPCh. 14 - Prob. 7STPCh. 14 - Prob. 8STPCh. 14 - Prob. 9STPCh. 14 - Prob. 10STPCh. 14 - Prob. 11STPCh. 14 - Prob. 12STPCh. 14 - Prob. 13STPCh. 14 - Prob. 14STPCh. 14 - Prob. 15STPCh. 14 - Prob. 16STPCh. 14 - Prob. 17STPCh. 14 - Prob. 18STPCh. 14 - Prob. 19STP

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