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An airplane with a weight W and a total wing span b flies horizontally at a constant speed v. Use the airplane as a reference frame: that is, consider the airplane to be motionless and the air to flow past it with speed v. Suppose that a cylinder of air with diameter b is deflected downward by the wing (the cross section of the cylinder is the dashed circle in the figure). Show that the angle through which the cylinder stream is deflected (called the downwash angle) is determined by the formula sin
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Vector Mechanics for Engineers: Dynamics
- See attached please and thank youarrow_forwardPlease solve (d) and (e)arrow_forwardThe super-container vessel in the figure has a total mass displacement of 23000 long tons. This vessel towed by a tugboat with a=20° angle with horizontal. If a constant tension is applied as F=320 kN by the tugboat, please calculate the time to bring the vessel to a speed of 2 knot from the rest. At these low speeds, please neglect the hull resistance that created by the motion. Note: (1 long tons = 1016.05 kg, 1 knot=1.151 mi/hr= 0.5144 m/s) %3Darrow_forward
- We want to design a wagon system like the one below while filling the kiln with coal at the Coke factory inside Kardemir. In this system, we want the wagon to reach a speed of v= 1 m/s in t=2 seconds. It will then shoot at constant speed. How much engine power is required to tow a wagon with W= 500 kgf under these conditions P=? (Losses will be ignored). (The slope angle of the ramp is α= 25 degrees.)arrow_forwardAs seen in the figure, it has mass m1 and v isa bullet passes through a pendulum of mass m2 and its velocity v / 2exit with. Pendulum "L" long and mass negligibleIt is suspended on the end of a rope that can be carried. Your pendulum is a verticalminimum velocity v to move on the circlewhat should be min V?arrow_forwardThe super-container vessel in the figure has a total mass displacement of (4000) long tons. This vessel towed by a tugboat with α=20⁰ angle with horizontal. If a constant tension is applied as F= 400 kN by the tugboat, please calculate the time to bring the vessel to a speed of 2 knot from the rest. At these low speeds, please neglect the hull resistance that created by the motion. Note: (1 long tons = 1016.05 kg, 1 knot=1.151 mi/hr= 0.5144 m/s)arrow_forward
- A 1.86-kg block is held in place against the spring by a 81-N horizontal external force (see the figure). The external force is removed, and the block is projected with a velocity v1 = 1.2 m/s upon separation from the spring. The block descends a ramp and has a velocity v2 = 1.9 m/s at the bottom. The track is frictionless between points A and %3D B. The block enters a rough section at B, extending to E. The coefficient of kinetic friction over this section is 0.28. The velocity of the block is v3 = 1.4 m/s at C. The block moves on to D, where it stops. The height h of the ramp is closest to elle V4 smooth Barough Carrow_forwardHelp me in lift partarrow_forward1) We would like to design a wagon system as below when filling coal into the furnace at the Coke factory inside Kardemir. In this system, we want the wagon to reach a speed of v= 2 m/s in t=4 seconds. It will then shoot at constant speed. How much engine power is required to tow a wagon with W= 390 kgf under these conditions P=? (Losses will be ignored). (The slope angle of the ramp is α= 11 degrees.)arrow_forward
- The figure below shows a diver going through general motion. The diver's center of gravity can be assumed to undergo a projectile motion. Assume that the diver takes off from a diving board such that his center of gravity is a height ho = 11m above the water level and enters the water at a horizontal distance 1 = 4m from the end of the board. If the total time the diver remains in the air is t2 = 2.3s, calculate the speed, vo, and angle of takeoff ,O, of the diver's center of gravity. Also determine the height, hi, the diver reaches at the top of the dive. (Note that tr is NOT half of t2.)arrow_forwardPlease help mearrow_forwardfirst onearrow_forward
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