Chapter 12, Problem 48A

Interpretation Introduction

Interpretation:

The atmospheric pressure $84.0kPa$ needs to be converted to atm, and $torr$ unit.

Concept introduction:

 Atmospheric pressure is the force exerted by the air on a surface as gravity pulls it to Earth.

Answer to Problem 48A

$84.0kPa$ $=0.829atm$

$84.0kPa$ $=630torr$

Explanation of Solution

Given: Atmospheric pressure is equal to $84.0kPa$

$1atm$ = $101.325kPa$

Thus,

$\therefore 84.0kPa=84kPa\left(1atm/101.35kPa\right)$

Or,

$=0.829atm$

Also,

$$

$760torr$ = $101.325kPa$

Thus,

$\therefore 84.0kPa=84kPa\left(760torr/101.35kPa\right)$

Or,

$=630torr$

Conclusion

$84.0kPa$ $=0.829atm$

$84.0kPa$ $=630torr$