Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Textbook Question
Chapter 12, Problem 32P
A fragment of a wild
Wild
polypeptide |
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Mutant
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Mutant
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Mutant
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Mutant
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a. Use the available information to characterize each mutant.
b. Determine the wild
c. Identify the mutation that produces each mutant polypeptide.
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5'....TACTGCCCATGCCCAGAGAGAAAGCGCAGACGCGTCTAA actgt... 3'
a). (10 points). In the above sequences, the open reading frame is indicated by alternating
non-underlined and underlined triplets. Please use the codon table to deduce the amino
acid sequence for the region shown in the wildtype protein.
Wildtype AA sequence for the region around mutation #1:
Wildtype AA sequence for the region around mutation #2:
b). (10 points). Please make predictions what molecular change mutation #1 and mutation
#2 cause.
c). (5 points). Which mutation is more likely to abrogate the protein function? Why?
A particular protein has the amino acid sequenceN . . . Ala-Pro-His-Trp-Arg-Lys-Gly-Val-Thr . . . Cwithin its primary structure. A geneticist studyingmutations affecting this protein discovered that several of the mutants produced shortened protein molecules that terminated within this region. In one ofthem, the His became the terminal amino acid.a. What DNA single-base change(s) would cause theprotein to terminate at the His residue?b. What other potential sites do you see in the DNAsequence encoding this protein where mutation ofa single base pair would cause premature termination of translation?
The table shows the partial sequences of a wild type polypeptide and three mutant polypeptides as well as the type of single
nucleotide mutation that produced each mutant polypeptide.
Peptide sequence
Met - Leu - Arg - Ile - ...
Type of mutation
Wild type
Met - Leu - Arg - Met - ...
Met - Leu - [STOP]
Mutant 1
transition
Mutant 2
transversion
Mutant 3
Met - Phe - Arg - Ile - ...
transition
Determine the mRNA sequence for the wild type polypeptide by identifying the codons that correspond to each amino acid. The
first codon has been filled in for you. Codon information can be found in the codon access table.
Met
Leu
Arg
Ile
Answer Bank
CỦA
AUA
CGU
CGA
AUG
AUC
AGA
UUG
CÚC
Chapter 12 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 12 - 11.1 Identify two general ways chemical mutagens...Ch. 12 - 11.2 Nitrous acid and (BU) alter DNA by different...Ch. 12 - 11.19 Using the adeninethymine base pair in this...Ch. 12 - The partial amino acid sequence of a wild-type...Ch. 12 - 5. Thymine is usually in its normal, common form....Ch. 12 - Ultraviolet (UV) radiation is mutagenic.
What...Ch. 12 - Researchers interested in studying mutation and...Ch. 12 - The effect of base - pair substitution mutations...Ch. 12 - Prob. 9PCh. 12 - 11.10 In numerous population studies of...
Ch. 12 - 11.11 Two different mutations are identified in a...Ch. 12 - 11.22 Many human genes are known to have homologs...Ch. 12 - 11.13 Answer the following questions concerning...Ch. 12 - Prob. 14PCh. 12 - Prob. 15PCh. 12 - Prob. 16PCh. 12 - 11.15 A sample of the bacterium is exposed to...Ch. 12 - 11.16 A strain of is identified as having a null...Ch. 12 - Define gene conversion and contrast it with gene...Ch. 12 - Prob. 20PCh. 12 - Prob. 21PCh. 12 - Prob. 22PCh. 12 - Prob. 23PCh. 12 - Prob. 24PCh. 12 - 25. If homologous recombination did not occur,...Ch. 12 - In this chapter, three features of genes or of DNA...Ch. 12 - Briefly compare the production of DNA double -...Ch. 12 - During mismatch repair, why is it necessary to...Ch. 12 - 11.27 Following the spill of a mixture of...Ch. 12 - A geneticist searching for mutations uses the...Ch. 12 - A wild - type culture of haploid yeast is exposed...Ch. 12 - A fragment of a wild - type polypeptide is...Ch. 12 - Prob. 33PCh. 12 - 11.40 Common baker’s yeast () is normally grown at...Ch. 12 - 11.41 The two gels illustrated below contain...Ch. 12 - Alkaptonuria is a human autosomal recessive...Ch. 12 - 11.33 In an experiment employing the methods of...Ch. 12 - Using your knowledge of DNA repair pathways choose...Ch. 12 - 11.35 Ataxia telangiectasia is a human inherited...Ch. 12 - 40. Two haploid strains of fungus are fused to...
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- 5'......TACTGCCCATGCCCAGAGAGAAAGCGCAGACGCGTCTAAactgt... 3' a). (10 points). In the above sequences, the open reading frame is indicated by alternating non-underlined and underlined triplets. Please use the codon table to deduce the amino acid sequence for the region shown in the wildtype protein. Wildtype AA sequence for the region around mutation #1: Wildtype AA sequence for the region around mutation #2: b). (10 points). Please make predictions what molecular change mutation #1 and mutation #2 cause. c). (5 points). Which mutation is more likely to abrogate the protein function? Why?arrow_forwardWhich of the following sequences is most likely to form a beta-turn? Explain why? Sequence A: Ser-Pro-Asn-Val Sequence B: Gly-Ser-Asn-Pro Sequence C: Ser-Asn-Gly-Valarrow_forwardA wildtype gene produces the polypeptide sequence: Wildtype: Met-Ser-Pro-Arg-Leu-Glu-Gly Each of the following polypeptide sequences is the result of a single mutation. Identify the most likely type of mutation causing each, be as specific as possible. M1:Met-Ser-Ser-Arg-Leu-Glu-Gly missense mutation M2:Met-Ser-Pro M3:Met-Ser-Pro-Asp-Trp-Arg-Asp-Lys M4:Met-Ser-Pro-Glu-Gly nonsense mutation frameshift insertion in frame deletion M5:Met-Ser-Pro-Arg-Leu-Glu-Gly in frame insertionarrow_forward
- Suppose part of the amino acid sequence of a protein is N... Gly-Ala - Pro-Arg-Lys ...C. Which of the following amino acid sequences could result from a frameshift mutation (+1 or -1) in the part of the gene that encodes this sequence of amino acids? O O N... Gly- Ala-Asn - Ser - Leu ...C N...Ala-Ala-Arg-Pro - Lys...C N...Gly-Gly-Thr-Thr-Glu...C N... Gly-Ala-His-lle - Val ...C N... Gly-His-Thr - Met - Val ...Carrow_forwardWith this DNA sequenec: - 5'-GCAATGGAGAGAATCTGCGCG-3'- - 3'-CGTTACCTCTGTTAGACGCGC-5' - -Identify the sequencce of RNA in which the protein product will be detrnemined. -What will be the protein product sqeuence? -What will be the pl of the protein product?arrow_forwardGiven the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs ( what letter changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - AGGCTCGCCTGT - 5' Mutated DNA Sequence: 3' - AGTCTCGCCTGT - 5'arrow_forward
- What potential polypeptides can be produced from the following mRNA sequence? There are more than one answer.. 5’ ...GGAGCUCGUUGUAUU... 3’ a. ser-ser-leu-tyr b. leu-cys-cys-ser-arg c. gly-ala-ser-trp-ile d. gly-ala-arg-cys-ile e. glu-leu-val-val f. You can't translate without a start codon. I know (d) is one of the answer but I'm stuck on how to find the rest. Please help.arrow_forwardGiven the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs (what letters changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions (with spaces), and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - CCTCGTTATGTG - 5' Mutated DNA Sequence: 3' - CCTCGTTATTTG - 5'arrow_forwardYou have discovered a novel protein that has a pI = 5.5. To study the functional properties of this new protein, your research group has made a mutant that contains two amino acid changes—namely, a surface Phe residue in the normal protein has been replaced by His (side chain pKa = 6.1) and asurface Gln has been replaced by Glu (side chain pKa = 6.0). Is the pI of themutant protein predicted to be greater than, less than, or the same as the pIof the normal protein? Support your answer with the appropriate calculationarrow_forward
- Determine the isoelectric point of the peptide product of the mutated sequence: 5' - AUG UCC AUG AUU CUG GAA AUU ACC UCC AUC AUG AAG CGC UGA CCC AUU AUU AA - 3'arrow_forwardThe first 15 bases of the original coding informational strand of DNA (which continues after what is shown) are 5-ATGAAACCCGGGTTT(...)-3'. Which of the following mutations to this original strand would be silent and which would likely only have a small effect on the coded protein? (Again, only the first 15 bases of the DNA strand are shown, even though they continue on. HINT: To solve this, you might write out the template DNA strand, the mRNA strand that would be made, and the resulting amino acids for the start of the protein.) Mutation #1: 5-ATGAAAGCCCGGGTT(...)-3' Mutation #2: 5-ATGAACCCCGGGTTT(...)-3' Mutation #3: 5-ATGAACCCGGGTTTA(...)-3' Mutation #4: 5-ATGAAGCCCGGGTTT(...)-3' Mutation #5: 5-ATGTAACCCGGGTTT(...)-3'arrow_forwardThe protein encoded by the cystic fibrosis gene is 1480amino acids long, yet the gene spans 250 kb. How is thisdifference possible?arrow_forward
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