Concept explainers
Alkaptonuria is a human autosomal recessive disorder caused by mutation of the HAO gene that encodes the enzyme homogentisic acid oxidase. Restriction mapping
of the HAO gene region reveals four BamHI restriction sites
DNA samples taken from a mother (M), father (F), and two children
a. Using A to represent the
b. In a separate figure, draw the autoradiograph patterns for all the genotypes that could be found in children of this couple.
c. Explain how the DNA sequence change results in a
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Genetic Analysis: An Integrated Approach (2nd Edition)
- The restriction endonuclease NotI recognizes the octanucleotide sequence GCGGCCGC. Calculate the expected number of NotI cleavage sites in the bacteriophage λgenome, a linear DNA duplex 48.5 kbp in length with a (G + C) content of 50%.arrow_forwardThe restriction endonuclease NotI recognizes the octanucleotide sequence GCGGCCGC. Calculate the expected number of NotI cleavage sites in the bacteriophage l genome, a linear DNA duplex 48.5 kbp in length with a (G + C) content of 50%.arrow_forwardConsider the λ bacteriophage DNA molecule as shown in Figure 21.14. Total digestion with the two restriction endonucleases used does not allow unambiguous placement of restriction sites, as shown in the map. Describe restriction patterns—either from partial digestion or from digestion with both BamHI and EcoRI—that would help to establish the specific map of restriction sites shown in Figure 21.14(b).arrow_forward
- A 2.0kb bacterial plasmid ‘BS1030’ is digested with the restriction endonuclease Sau3A; the plasmid map is depicted in the diagram below and the Sau3A (S) restriction sites are indicated. Which of the following DNA fragments do you expect to see on an agarose gel when you run Sau3A-digested plasmid ‘BS1030’ DNA? a. 250 bp, 450 bp, 550 bp, 1.1 kb, 1.5 kb and 2.0 kb b. 2.0kb c. 250 bp, 400 bp, 450 bp, 500 bp and 550 bp d. 100 bp, 200 bp, 250 bp, 400 bp, 500 bp and 550 bparrow_forwardYou are studying a protein that contains the peptide sequence RDGSWKLVI. The part of the DNA encoding this peptide is included in the sequence shown below. 5'-CGTGACGGCTCGTGGAAGCTAGTCATC-3' 3'-GCACTGCCGAGCACCTTCGATCAGTAG-5' This sequence does not contain any BamHI restriction enzyme sites. The target sequence for the BamHI restriction nuclease is GGATCC. Your goal is to create a BamHI site on this plasmid by manipulating the DNA sequence, without changing the coding sequence of the protein. How would you do this, ie what would the new sequence be?arrow_forwardGenomic DNA from a family where sickle-cell disease is known to be hereditary, is digested with the restriction enzyme MstII and run in a Southern Blot. The blot is hybridised with two different 0.6 kb probes, both probes (indicated in red in the diagram below) are specific for the β-globin gene (indicated as grey arrow on the diagram below). The normal wild-type βA allele contains an MstII restriction site indicated with the asterisk (*) in the diagram below; in the mutated sickle-cell βS allele this restriction site has been lost. What size bands would you expect to see on the Southern blots using probe 1 and probe 2 for an individual with sickle cell disease (have 2 βS alleles)? Probe 1 Probe 2 (a) 0.6kb 0.6kb and 1.2kb (b) 0.6kb and 1.8kb 0.6kb, 1.2kb and 1.8kb (c) 1.2kb 0.6kb (d) 1.8kb 1.8kb a. (a) b. (b) c. (c) d. (d)arrow_forward
- For the DNA sequence shown, indicate the products of its cleavage with the following restriction endonucleases (AKA restriction enzymes):5′-ACAGCTGATTCGAATTCACGTT-3′3′-TGTCGACTAAGCTTAAGTGCAA-5′a) EcoRI (the recognition sequence and cleavage site is G↓AATTC);b) AluI (the recognition sequence and cleavage site is AG↓CT).arrow_forwardDecide on two restriction sites that you can use to clone this into pL4440’s MCS. Identify their sequence. Tip: The plasmid map is in Figure 3, details of restriction site sequences can be found at https://enzymefinder.neb.com/#!#nebheaderarrow_forwardTable 1 shows a list of restriction endonucleases with their recognition sequence and the sites of cleavage indicated by arrows. Table 1 Enzyme name Recognition sequence and position of cut 5'GIAATTC3 5'G!GATCC3' 5'GIGTACC3 5'GCIGGCCGC3' 5'IGATC3' 5'GGTACIC3' 5'ALGATCT3 EcoRI ВатHI Аcс651 Notl Sau3A Kpnl BglII (i) Which restriction enzyme(s) produce blunt ends? (ii) Are there any pair of neoschizomers in the list? Explain. (iii) Are there any pair of isocaudomers in the list? Explain.arrow_forward
- Kpn I and Acc 65I are restriction enzymes that identify and cleave the same 6-bp sequence. The sticky end created by Kpn I cleavage, on the other hand, cannot be directly ligated to the sticky end formed by Acc 65I cleavage. Please explain why.arrow_forwardMutation analysis of GCK gene in patients with diabetes revealed a c.114 T A (shown in bold and underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals, restriction enzyme analysis will be used. a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below. b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and heterozygote individual after restriction enzyme analysis. ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGC TGAGGCCACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAG AATCCCCCACTCCACACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAG GCTAGGATGTGA Figure 1. GCK gene sequence. Length of the fragment is 213bp. Table1. The restriction enzymes and their recognition sequences. Restriction enzyme Recognition seguence Nar I GG/CGCC Dde I c/TNAG…arrow_forwardUsing the plasmid map of pBCH2.0 provided above, predict how many DNA fragments would be formed if this plasmid was digested with restriction enzyme BamHI.arrow_forward
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