24) Use the following information to answer the question below.Researchers studying a small milkweed population note that some plants produce a toxin and other plants do not.They identify the gene responsible for toxin production. The dominant allele (T) codes for an enzyme that makesthe toxin, and the recessive allele (t) codes for a nonfunctional enzyme that cannot produce the toxin.Heterozygotes produce an intermediate amount of toxin. The genotypes of all individuals in the population aredetermined (see table) and used to determine the actual allele frequencies in the population.TT0.49Tt0.42tt0.09Refer to the table above. Is this population in Hardy-Weinberg equilibrium?A) Yes.C) No; there are more homozygotes than expected.B) No; there are more heterozygotes than expected.D) It is impossible to tell.

Approach to solving the question:To check if a population is in HWE, we need to see if the observed…

Answered: 24) Use the following information to…

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 4CT: The young woman shown at right has albinismvery pale skin, white hair, and pale blue eyes. This...

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Figure 13.4 Which of the following statements is true? Recombination of the body color and red/ cinnabar eye alleles will occur more frequently than recombination of the alleles for wing length and aristae length. Recombination of the body color and aristae length alleles will occur more frequently than recombination of red/brown eye alleles and the aristae length alleles. Recombination of the gray/black body color and long/short aristae alleles will not occur. Recombination of the red/brown eye and long/short aristae alleles will occur more frequently than recombination of the alleles for wing length and body color.
Half of the worlds population eats rice at least twice a day. Much of this rice is grown in flooded conditions, and different strains of rice are tolerant (survive) or intolerant (die) under these conditions. Rice breeders used genetic crosses to test whether tolerance to flooding is a dominant trait. Researchers used three true-breeding flood-tolerant strains, FR143, BKNFR, and Kurk, and two true-breeding flood- intolerant strains, IR42 and NB, in the crosses. Results were obtained from three sets of crosses and are reported in the Table below: Results of cross of F1 to tolerant parent: F1 plants were crossed with the tolerant parent of the cross. Number of Plants Progeny Analyzed from Intolerant Tolerant Cross Alive Dead Total 1. F2 results of cross: IR42 FR13A 187 77 264 IR42 BKNFR 192 73 265 NB Kurk 142 52 195 2. Results of cross of F1 to intolerant parent: (F1 of IR42 FR13A) IR42 14 17 31 (F1 of IR42 BKNFR) IR42 15 10 25 (F1 of NB Kurk) NB 21 35 56 3. Results of cross of F1 to tolerant parent: (F1 of IR42 FR13A) FR13A 31 0 31 (F1 of IR42 BKNFR) BKNFR 28 0 28 (F1 of NB Kurk) Kurk 40 0 40 Do the data support the hypothesis that the tolerance trait is dominant? Justify your conclusion by explaining the results from each of the three sets of crosses in terms of genotypes and phenotypic ratios. Source: T. Setter et al. 1997. Physiology and genetics of submergence tolerance in rice. Annals of Botany 79:6777.
The reason spontaneous mutations do not have an immediate effect on allele frequencies in a large population is that: a. mutations are random events, and mutations may be eitherbeneficial or harmful. b. mutations usually occur in males and have little effect oneggs. c. many mutations exert their effects after an organism hasstopped reproducing. d. mutations are so rare that mutated alleles are greatlyoutnumbered by nonmutated alleles. e. most mutations do not change the amino acid sequence of aprotein.
A farmer raises black and white chickens. To his surprise, when the first generation of eggs hatch all the chickens are black with white speckles throughout their feathers. What should the farmer expect when the eggs laid after interbreeding the speckled chickens hatch? All the offspring will be speckled 75% of the offspring will be speckled, and 25% will be black 50% of the offspring will be speckled, 25% will be black, and 25% will be white 50% of the offspring will be black and 50% of the offspring will be white.
In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grain (l). Bateson and Punnett crossed a plant having purple flowers/long pollen grains with one having white/flowers/round pollen grains. All F1 offspring had purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple flowers/round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
If the genotype frequencies in a population are 0.60 AA, 0.20 Aa, and 0.20 aa, and if the requirements of the HardyWeinberg principle apply, the genotype frequencies in the offspring generation will be: a. 0.60 AA, 0.20 Aa, 0.20 aa. b. 0.36 AA, 0.60 Aa, 0.04 aa. c. 0.49 AA, 0.42 Aa, 0.09 aa. d. 0.70 AA, 0.00 Aa, 0.30 aa. e. 0.64 AA, 0.32 Aa, 0.04 aa.
Which recombination frequency corresponds to perfect linkage and violates the law of independent assortment? 0 0.25 0.50 0.75
A walnut comb rooster is mated to three hens. Hen A, which has a walnut comb, has offspring in the ratio of 3 walnut to 1 rose. Hen B, which has a pea comb, has offspring in the ratio of 3 walnut to 3 pea to 1 rose to 1 single. Hen C, which has a walnut comb, has only walnut comb offspring. What are the genotypes of the rooster and the three hens?
Similarities in ___________ are the basis of similarities in traits. a. karyotype c. the double helix b. DNA sequence d. chromosome number
Which recombination frequency corresponds to independent assortment and the absence of linkage? 0 0.25 0.50 0.75
Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?
A proband female with an unidentified disease seeks the advice of a genetic counselor before starting a family. Based on the following data, the counselor constructs a pedigree encompassing three generations: (1) The maternal grandfather of the proband has the disease. (2) The mother of the proband is unaffected and is the youngest of five children, the three oldest being male. (3) The proband has an affected older sister, but the youngest siblings are unaffected twins (boy and girl). (4) All the individuals who have the disease have been revealed. Duplicate the counselors feat

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