Chapter 12, Problem 12.77SP

Interpretation Introduction

Interpretation:

Two chemical reactions have same activation energy $\left({\text{E}}_{\text{a}}\right)$ but their rates at the same temperature differ by a factor of 10, explanation for this observation has to be given.

Concept introduction:

Arrhenius equation:

The dependence of the rate constant $\left(\text{k}\right)$ of a chemical reaction on the activation energy, gas constant and temperature is given by Arrhenius equation.

$\begin{array}{l}\text{k}\text{=}{\text{Ae}}^{{\text{-E}}_{\text{a}}\text{/RT}}\\ \text{where,}\\ \text{k}\text{-}\text{rate}\text{constant}\\ \text{A}\text{-}\text{frequency}\text{factor}\left(\text{=}\text{pZ}\right)\\ {\text{E}}_{\text{a}}\text{-}\text{activation}\text{energy}\\ \text{R}\text{-}\text{gas}\text{constant}\text{and}\text{T-}\text{temperature}\text{.}\end{array}$