Reason behind more negative electron affinity for S than O should be given. Concept introduction: In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy. The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons. Reverse of ionization process may result in a gain of one or more electron as exhibited by groups 16 and 17 to attain noble core configuration. These groups have 6 and seven valence electrons and hence favorably accept 2 and 1 electron respectively. This behavior is termed as electron affinity.
Reason behind more negative electron affinity for S than O should be given. Concept introduction: In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy. The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons. Reverse of ionization process may result in a gain of one or more electron as exhibited by groups 16 and 17 to attain noble core configuration. These groups have 6 and seven valence electrons and hence favorably accept 2 and 1 electron respectively. This behavior is termed as electron affinity.
Solution Summary: The author explains the reason behind more negative electron affinity for S than
Definition Definition Change in energy of a neutral gaseous atom when an electron is added to the atom to form a negative ion.
Chapter 12, Problem 117E
Interpretation Introduction
Interpretation:Reason behind more negative electron affinity for S than O should be given.
Concept introduction: In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy.
The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons.
Reverse of ionization process may result in a gain of one or more electron as exhibited by groups 16 and 17 to attain noble core configuration. These groups have 6 and seven valence electrons and hence favorably accept 2 and 1 electron respectively. This behavior is termed as electron affinity.
The Concept of Aromaticity
21.15 State the number of 2p orbital electrons in each molecule or ion.
(a)
(b)
(e)
(f)
(c)
(d)
(h)
(i)
DA
(k)
21.16 Which of the molecules and ions given in Problem 21.15 are aromatic according to the
Hückel criteria? Which, if planar, would be antiaromatic?
21.17 Which of the following structures are considered aromatic according to the Hückel
criteria?
---0-0
(a)
(b)
(c)
(d)
(e)
(h)
H
-H
.8.0-
21.18 Which of the molecules and ions from Problem 21.17 have electrons donated by a
heteroatom?
1. Show the steps necessary to make 2-methyl-4-nonene using a
Wittig reaction. Start with triphenylphosphine and an alkyl
halide. After that you may use any other organic or inorganic
reagents.
2. Write in the product of this reaction:
CH3
CH₂
(C6H5)₂CuLi
H₂O+
3. Name this compound properly, including stereochemistry.
H₂C
H3C
CH3
OH
4. Show the step(s) necessary to transform the compound on the
left into the acid on the right.
Bri
CH2
5. Write in the product of this
LiAlH4
Br
H₂C
OH
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