a.
To calculate: The area of shaded region which contains concentric
a.
Answer to Problem 20PSC
The area of shaded region is
Explanation of Solution
Given information:
A radius of inner circle is 6 and outer circle is 12.
Formula used:
Area of a circle:
r = radius of circle.
Area of
Area of sector
r = radius of circle.
Calculation:
b.
To find: The area of shaded region which contains semicircles.
b.
Answer to Problem 20PSC
The area of shaded region is
Explanation of Solution
Given information:
Two semicircles with radius 3 and 6.
Formula used:
Area of a circle:
r = radius of circle.
R = radius of outer circle.
r = radius of inner circle.
Calculation:
The shaded figure becomes circle with radius
c.
To find: The area of shaded region which contains triangle.
c.
Answer to Problem 20PSC
The area of shaded part is
Explanation of Solution
Given information:
An equilateral triangle with sides as 12.The measure of arc is
Formula used:
Area of equilateral triangle:
s = side of equilateral triangle.
Area of sector
r = radius of circle.
Calculation:
The shaded area is formed by subtracting two sectors from the triangle and then adding five circles in the circle.
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