Chapter 11.1, Problem 10PSB

To determine

To find : The area of the given frame

Answer to Problem 10PSB

The area is $A=88$

Explanation of Solution

Given information : The following information has been given

Length of bigger rectangle $l_1=30+2=32$

Width of bigger rectangle $w_1=12+2=14$

Length of smaller rectangle $l_2=30$

Width of smaller rectangle $w_2=12$

Formula used : The area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)$

Calculation : We know that the area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)-(lengt{h}_2)(widt{h}_2)$

Hence, substituting the values from the given information, we get

  $A=(32)(14)-(30)(12)=88$

Thus, we get

  $A=88$