Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
expand_more
expand_more
format_list_bulleted
Question
Chapter 11.5, Problem 8PSA
To determine
To calculate : The side length of the equilateral
Expert Solution & Answer

Answer to Problem 8PSA
The side length
Explanation of Solution
Given information : The area of the equilateral triangle is,
Formula used : Thearea of an equilateral triangle is as follows:
Where
“ a ” is the side of the equilateral triangle.
Calculation : The area of the triangle is
Substituting the value of
Thus, we get
Chapter 11 Solutions
Geometry For Enjoyment And Challenge
Ch. 11.1 - Prob. 1PSACh. 11.1 - Prob. 2PSACh. 11.1 - Prob. 3PSACh. 11.1 - Prob. 4PSACh. 11.1 - Prob. 5PSACh. 11.1 - Prob. 6PSACh. 11.1 - Prob. 7PSACh. 11.1 - Prob. 8PSBCh. 11.1 - Prob. 9PSBCh. 11.1 - Prob. 10PSB
Ch. 11.1 - Prob. 11PSBCh. 11.1 - Prob. 12PSBCh. 11.1 - Prob. 13PSBCh. 11.1 - Prob. 14PSBCh. 11.1 - Prob. 15PSBCh. 11.1 - Prob. 16PSCCh. 11.1 - Prob. 17PSCCh. 11.2 - Prob. 1PSACh. 11.2 - Prob. 2PSACh. 11.2 - Prob. 3PSACh. 11.2 - Prob. 4PSACh. 11.2 - Prob. 5PSACh. 11.2 - Prob. 6PSACh. 11.2 - Prob. 7PSACh. 11.2 - Prob. 8PSACh. 11.2 - Prob. 9PSACh. 11.2 - Prob. 10PSACh. 11.2 - Prob. 11PSACh. 11.2 - Prob. 12PSACh. 11.2 - Prob. 13PSBCh. 11.2 - Prob. 14PSBCh. 11.2 - Prob. 15PSBCh. 11.2 - Prob. 16PSBCh. 11.2 - Prob. 17PSBCh. 11.2 - Prob. 18PSBCh. 11.2 - Prob. 19PSBCh. 11.2 - Prob. 20PSBCh. 11.2 - Prob. 21PSBCh. 11.2 - Prob. 22PSBCh. 11.2 - Prob. 23PSBCh. 11.2 - Prob. 24PSBCh. 11.2 - Prob. 25PSBCh. 11.2 - Prob. 26PSCCh. 11.2 - Prob. 27PSCCh. 11.2 - Prob. 28PSCCh. 11.2 - Prob. 29PSCCh. 11.2 - Prob. 30PSCCh. 11.2 - Prob. 31PSCCh. 11.2 - Prob. 32PSCCh. 11.2 - Prob. 33PSCCh. 11.3 - Prob. 1PSACh. 11.3 - Prob. 2PSACh. 11.3 - Prob. 3PSACh. 11.3 - Prob. 4PSACh. 11.3 - Prob. 5PSACh. 11.3 - Prob. 6PSACh. 11.3 - Prob. 7PSBCh. 11.3 - Prob. 8PSBCh. 11.3 - Prob. 9PSBCh. 11.3 - Prob. 10PSBCh. 11.3 - Prob. 11PSBCh. 11.3 - Prob. 12PSBCh. 11.3 - Prob. 13PSBCh. 11.3 - Prob. 14PSCCh. 11.3 - Prob. 15PSCCh. 11.3 - Prob. 16PSCCh. 11.3 - Prob. 17PSCCh. 11.3 - Prob. 18PSCCh. 11.3 - Prob. 19PSCCh. 11.3 - Prob. 20PSCCh. 11.4 - Prob. 1PSACh. 11.4 - Prob. 2PSACh. 11.4 - Prob. 3PSACh. 11.4 - Prob. 4PSBCh. 11.4 - Prob. 5PSBCh. 11.4 - Prob. 6PSBCh. 11.4 - Prob. 7PSBCh. 11.4 - Prob. 8PSBCh. 11.4 - Prob. 9PSBCh. 11.4 - Prob. 10PSCCh. 11.4 - Prob. 11PSCCh. 11.4 - Prob. 12PSCCh. 11.4 - Prob. 13PSCCh. 11.5 - Prob. 1PSACh. 11.5 - Prob. 2PSACh. 11.5 - Prob. 3PSACh. 11.5 - Prob. 4PSACh. 11.5 - Prob. 5PSACh. 11.5 - Prob. 6PSACh. 11.5 - Prob. 7PSACh. 11.5 - Prob. 8PSACh. 11.5 - Prob. 9PSACh. 11.5 - Prob. 10PSACh. 11.5 - Prob. 11PSACh. 11.5 - Prob. 12PSBCh. 11.5 - Prob. 13PSBCh. 11.5 - Prob. 14PSBCh. 11.5 - Prob. 15PSBCh. 11.5 - Prob. 16PSBCh. 11.5 - Prob. 17PSBCh. 11.5 - Prob. 18PSBCh. 11.5 - Prob. 19PSCCh. 11.5 - Prob. 20PSCCh. 11.5 - Prob. 21PSCCh. 11.5 - Prob. 22PSCCh. 11.5 - Prob. 23PSCCh. 11.5 - Prob. 24PSCCh. 11.5 - Prob. 25PSCCh. 11.5 - Prob. 26PSCCh. 11.6 - Prob. 1PSACh. 11.6 - Prob. 2PSACh. 11.6 - Prob. 3PSACh. 11.6 - Prob. 4PSACh. 11.6 - Prob. 5PSACh. 11.6 - Prob. 6PSACh. 11.6 - Prob. 7PSACh. 11.6 - Prob. 8PSBCh. 11.6 - Prob. 9PSBCh. 11.6 - Prob. 10PSBCh. 11.6 - Prob. 11PSBCh. 11.6 - Prob. 12PSBCh. 11.6 - Prob. 13PSBCh. 11.6 - Prob. 14PSBCh. 11.6 - Prob. 15PSBCh. 11.6 - Prob. 16PSBCh. 11.6 - Prob. 17PSBCh. 11.6 - Prob. 18PSCCh. 11.6 - Prob. 19PSCCh. 11.6 - Prob. 20PSCCh. 11.6 - Prob. 21PSCCh. 11.6 - Prob. 22PSCCh. 11.6 - Prob. 23PSCCh. 11.7 - Prob. 1PSACh. 11.7 - Prob. 2PSACh. 11.7 - Prob. 3PSACh. 11.7 - Prob. 4PSACh. 11.7 - Prob. 5PSACh. 11.7 - Prob. 6PSACh. 11.7 - Prob. 7PSACh. 11.7 - Prob. 8PSACh. 11.7 - Prob. 9PSBCh. 11.7 - Prob. 10PSBCh. 11.7 - Prob. 11PSBCh. 11.7 - Prob. 12PSBCh. 11.7 - Prob. 13PSBCh. 11.7 - Prob. 14PSBCh. 11.7 - Prob. 15PSBCh. 11.7 - Prob. 16PSBCh. 11.7 - Prob. 17PSBCh. 11.7 - Prob. 18PSCCh. 11.7 - Prob. 19PSCCh. 11.7 - Prob. 20PSCCh. 11.7 - Prob. 21PSCCh. 11.7 - Prob. 22PSCCh. 11.8 - Prob. 1PSACh. 11.8 - Prob. 2PSACh. 11.8 - Prob. 3PSACh. 11.8 - Prob. 4PSBCh. 11.8 - Prob. 5PSBCh. 11.8 - Prob. 6PSBCh. 11.8 - Prob. 7PSBCh. 11.8 - Prob. 8PSBCh. 11.8 - Prob. 9PSBCh. 11.8 - Prob. 10PSBCh. 11.8 - Prob. 11PSCCh. 11.8 - Prob. 12PSCCh. 11.8 - Prob. 13PSCCh. 11 - Prob. 1RPCh. 11 - Prob. 2RPCh. 11 - Prob. 3RPCh. 11 - Prob. 4RPCh. 11 - Prob. 5RPCh. 11 - Prob. 6RPCh. 11 - Prob. 7RPCh. 11 - Prob. 8RPCh. 11 - Prob. 9RPCh. 11 - Prob. 10RPCh. 11 - Prob. 11RPCh. 11 - Prob. 12RPCh. 11 - Prob. 13RPCh. 11 - Prob. 14RPCh. 11 - Prob. 15RPCh. 11 - Prob. 16RPCh. 11 - Prob. 17RPCh. 11 - Prob. 18RPCh. 11 - Prob. 19RPCh. 11 - Prob. 20RPCh. 11 - Prob. 21RPCh. 11 - Prob. 22RPCh. 11 - Prob. 23RPCh. 11 - Prob. 24RPCh. 11 - Prob. 25RPCh. 11 - Prob. 26RPCh. 11 - Prob. 27RPCh. 11 - Prob. 28RPCh. 11 - Prob. 29RPCh. 11 - Prob. 30RPCh. 11 - Prob. 31RPCh. 11 - Prob. 32RPCh. 11 - Prob. 33RPCh. 11 - Prob. 34RPCh. 11 - Prob. 35RPCh. 11 - Prob. 36RPCh. 11 - Prob. 37RPCh. 11 - Prob. 38RPCh. 11 - Prob. 39RPCh. 11 - Prob. 40RPCh. 11 - Prob. 41RPCh. 11 - Prob. 42RPCh. 11 - Prob. 43RPCh. 11 - Prob. 44RPCh. 11 - Prob. 45RP
Additional Math Textbook Solutions
Find more solutions based on key concepts
x 2 3x100
Precalculus
In hypothesis testing, the common level of significance is =0.05. Some might argue for a level of significance ...
Basic Business Statistics, Student Value Edition
Find the lengths of the curves in Exercises 21–28.
27. The curve
University Calculus: Early Transcendentals (4th Edition)
Calculate following proportion 637=y100
Pre-Algebra Student Edition
Fill in each blanks so that the resulting statement is true. Any set of ordered pairs is called a/an _______. T...
College Algebra (7th Edition)
Find how many SDs above the mean price would be predicted to cost.
Intro Stats, Books a la Carte Edition (5th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.Similar questions
- MI P X /courses/segura10706/products/171960/pages/611?locale=&platformId=1030&lms=Y ☆ Finish Part I: Mathematics for Elementary and Middle School Teachers Continue in the app JJ 576 Chapter 12. Area of Shapes 9. Determine the area of the shaded shapes in Figure 12.48. Explain your reasoning. 1 unit S Figure 12.48 1 unit unit and the yarn for thearrow_forwardChrom ESS $425 5. Ar Dive for x 21) Name 1. Classify the triangles based on their side lengths and angle measures. 89° 30° Acute Scalene Right Scalene 130° Date A +100 Obtuse Equiangular Isosceles Equilateral What additional information would you need to prove these triangles congruent by ASA? If marrow_forwardBoth find out Only 100% sure experts solve it correct complete solutions okkk don't use chat gpt or other ai okkarrow_forwardOnly 100% sure experts solve it correct complete solutions okkk don't use chat gpt or other ai okkarrow_forwardLogin HAC Home View Summary MwMerriam-Webster: A... Lizard Point Quizze... G Home | Gimkit Quizlet Live | Quizlet K! Kahoot! 7.2 HW Central Angles, Arcs, and Arc Lengths POSSIBLE POINTS: 6.67 11. If myQ=(y+7), mQR = (x+11), mRS = (3y), and mST = 65°, find the values of x and y. R V X = y = W S T q W a It N S C % 65 54 # m d DELL 96 t y 0 27 & J * 00 8 x= y= f g h J k X C V b n 3 ES 1 Feb 26 alt ctrlarrow_forwardThe three right triangles below are similar. The acute angles LL, LR, and ZZ are all approximately measured to be 66.9°. The side lengths for each triangle are as follows. Note that the triangles are not drawn to scale. Z 20.17 m 60.51 m 66.9° 7.92 m 66.9° 80.68 m 66.9° 23.76 m 31.68 m Take one 18.55 m K P 55.65 m X 74.2 m Y (a) For each triangle, find the ratio of the length of the side opposite 66.9° to the length of the hypotenuse. Round your answers to the nearest hundredth. JK JL PQ PR XY ☐ XZ (b) Use the ALEKS Calculator to find sin 66.9°, cos 66.9°, and tan 66.9°. Round your answers to the nearest hundredth. sin 66.9° = ☐ cos 66.9° tan 66.9° = ☐ (c) Which trigonometric function gives each ratio of sides in part (a)? Osine Ocosine Otangent none of thesearrow_forwardT Figure E Statement 33 33° H 40 R 37° 83° S T 55 45 K S 30 U 44 87 H 56 36 ° 54 F 83° 66 P 33 87° ° I 42 200 Rarrow_forwardStella's friends got her a skydiving lesson for her birthday. Her helicopter took off from the skydiving center, ascending in an angle of 37°, and traveled a distance of 2.1 kilometers before she fell in a straight line perpendicular to the ground. How far from the skydiving center did Stella land? Be sure to have all three parts of a CER answer: make a claim, provide evidence, and explain your reasoning for full credit. 2.1 km Landing spot 37% Skydiving centerarrow_forwardIn the graph provided, triangle N'O'P' is the image of triangle NOP after a dilation. 104 -9- -8- 7 6 N 5 0 -4- N 3 2 1 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 -1 -2 -3 -4 p -5 -6 -7 -8 Xarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning

Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,

Elementary Geometry for College Students
Geometry
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Cengage Learning
An Introduction to Area | Teaching Maths | EasyTeaching; Author: EasyTeaching;https://www.youtube.com/watch?v=_uKKl8R1xBM;License: Standard YouTube License, CC-BY
Area of a Rectangle, Triangle, Circle & Sector, Trapezoid, Square, Parallelogram, Rhombus, Geometry; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=JnLDmw3bbuw;License: Standard YouTube License, CC-BY