Chapter 11.1, Problem 9PSB

To determine

To find : The area of figure given in the question

Answer to Problem 9PSB

The area is $A=256$

Explanation of Solution

Given information : The following information has been given

Length of bigger rectangle $l_1=20$

Width of bigger rectangle $w_1=4$

Length of smaller rectangle $l_2=20$

Width of smaller rectangle $w_2=4$

Length of smaller rectangle $l_3=8$

Width of smaller rectangle $w_3=12$

Formula used : The area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)$

Calculation : We know that the area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)+(lengt{h}_2)(widt{h}_2)+(lengt{h}_3)(widt{h}_3)$

Hence, substituting the values from the given information, we get

  $A=(20)(4)+(20)(4)+(8)(12)=256$

Thus, we get

  $A=256$