Chapter 11.2, Problem 5PSA

To determine

To find : The area of the given isosceles triangle

Answer to Problem 5PSA

The area is $48$

Explanation of Solution

Given information : The following information has been given

The sides of the triangle are $10$ , $10$ , and $16$

Formula used : The area of any triangle will be

  $A=\frac{1}{2}(base)(height)$

Calculation : We assume a right triangle with altitude from vertex to the base side of the triangle. Hence, we get

  $a=\sqrt{{10}^2-8^2}\to a=6$

Where a is the altitude of the triangle for the base equals to $16$ .

Thus, we find the area as

  $A=\frac{1}{2}(base)(altitude)$

Thus, substituting the values, we get

  $A=\frac{1}{2}(16)(6)\to A=48$