Chapter 11.7, Problem 1PSA

a.

To determine

Find the ratio of the areas.

Answer to Problem 1PSA

  $1:1$

Explanation of Solution

Given information:

Compute the area of given figure,

  

Calculation:

Consider the figure,

  

Compute the area,

  $\begin{array}{l}Are{a}_1=bh\\ =10\times 9\\ =90squareunit\\ Are{a}_2=bh\\ =10\times 9\\ =90squareunit\\ Ratio=1:1\end{array}$

Hence, $Ratio=1:1$

b.

To determine

Find the ratio of the areas.

Answer to Problem 1PSA

  $1:2$

Explanation of Solution

Given information:

Compute the area of given figure,

  

Calculation:

Consider the figure,

  

Compute the area,

  $\begin{array}{l}Are{a}_1=\frac{1}{2}bh\\ =\frac{1}{2}\times 8\times 5\\ =20squareunit\\ Are{a}_2=\frac{1}{2}bh\\ =\frac{1}{2}\times 16\times 5\\ =40squareunit\\ Ratio=1:2\end{array}$

Hence, $Ratio=1:2$

c.

To determine

Find the ratio of the areas.

Answer to Problem 1PSA

  $15:8$

Explanation of Solution

Given information:

Compute the area of given figure,

  

Calculation:

Consider the figure,

  

Compute the area,

  $\begin{array}{l}Are{a}_1=\frac{1}{2}bh\\ =\frac{1}{2}\times 10\times 6\\ =30squareunit\\ Are{a}_2=\frac{1}{2}bh\\ =\frac{1}{2}\times 4\times 8\\ =16squareunit\\ Ratio=15:8\end{array}$

Hence, $Ratio=15:8$

d.

To determine

Find the ratio of the areas.

Answer to Problem 1PSA

  $5:6$

Explanation of Solution

Given information:

Compute the area of given figure,

  

Calculation:

Consider the figure,

  

Compute the area,

  $\begin{array}{l}Are{a}_1=\frac{1}{2}bh\\ =\frac{1}{2}\times 2\times 5\\ =5squareunit\\ Are{a}_2=\frac{1}{2}bh\\ =\frac{1}{2}\times 4\times 3\\ =6squareunit\\ Ratio=5:6\end{array}$

Hence, $Ratio=5:6$