Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Textbook Question

Chapter 11.3, Problem 11.61P

A particle moves in a straight line with a constant acceleration of -4 ft/s² for 6 s, zero acceleration for the next 4 s, and a constant acceleration of +4 ft/s² for the next 4 s. Knowing that the particle starts from the origin and that its velocity is -8 ft/s during the zero acceleration time interval, (a) construct the v − t and x − t curves for 0 ≤ t ≤ 14 s, (b) determine the position and the velocity of the particle and the total distance traveled when t = 14 s.

Chapter 11.3, Problem 11.61P, A particle moves in a straight line with a constant acceleration of -4 ft/s2 for 6 s, zero

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Chapter 11.2, Problem 11.60P

Chapter 11.3, Problem 11.62P

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The rectangular coordinates of a particle which moves with curvilinear motion are given by x = 10.75t +2.25t² - 0.45t³ and y = 6.90 + 17.43t - 2.62t², where x and y are in millimeters and the time t is in seconds, beginning from t = 0. Determine the velocity v and acceleration a of the particle when t = 8 s. Also, determine the first time that the velocity of the particle makes an angle of 30° with the positive x-axis. Answers: V = a = 17.1 10.75 i + i 5.24 i+ i 17.43 j) mm/s j) mm/s²

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Chapter 11 Solutions

Vector Mechanics for Engineers: Dynamics

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Solution Summary: The author explains how to determine the v-t curve, based on the area under the curve.

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